Bourbaki

Exercise 4, § 7

Algebra, I, 160

Bourbaki marks this one as harder than the rest.

Let XX be a set and cc an element not belonging to XX. We write Y=X∪{c}Y = X \cup \{c\}. Let MM be the magma with underlying set Mo(Y)Mo(Y) and law of composition given by (u,v)↦cuv(u, v) \mapsto cuv. Let LL be the submagma of MM generated by XX and let ε\varepsilon be the mapping from YY to Z\mathbf{Z} equal to −1-1 on XX and to 11 at cc.

(a) Show that LL is the subset of MM consisting of the words w=y1…ypw = y_1 \ldots y_p, yi∈Yy_i \in Y, satisfying the two following conditions: (i) ε(y1)+⋯+ε(yp)=−1\varepsilon(y_1) + \cdots + \varepsilon(y_p) = -1 (ii) ε(y1)+⋯+ε(yi)⩾0\varepsilon(y_1) + \cdots + \varepsilon(y_i) \geqslant 0 for 1⩽i⩽p−11 \leqslant i \leqslant p - 1. Show that every element of L−XL - X may be written uniquely in the form cuvcuv with u,v∈Lu, v \in L.

(The elements ww satisfying (i) and (ii) form a submagma L′L' of MM containing XX. If w=y1…ypw = y_1 \ldots y_p belongs to L′L', let kk be the least integer such that ε(y1)+⋯+ε(yk)=0\varepsilon(y_1) + \cdots + \varepsilon(y_k) = 0; show that y1=cy_1 = c and that the elements u=y2…yku = y_2 \ldots y_k and v=yk+1…ypv = y_{k+1} \ldots y_p belong to L′L'; then w=cuvw = cuv, whence by induction on pp the relation w∈Lw \in L. Then show that the relations u′,v′∈Lu', v' \in L and w=cu′v′w = cu'v' imply u′=u,v′=vu' = u, v' = v.)

(b) Show that the injection of XX into LL extends to an isomorphism of M(X)M(X) onto LL.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.