Bourbaki

Exercise 7, § 7

Tag 05G4, permanent. Cite it as [Bourbaki, Tag 05G4].

Algebra, I, 161

Bourbaki marks this one as harder than the rest.

Let MxM_x be the free magma constructed on a set {x}\{x\} with one element.

(a) For all y∈Mxy \in M_x, show that there exists a unique endomorphism fyf_y of MxM_x such that fy(x)=yf_y(x) = y; it is an isomorphism of MxM_x onto the submagma MyM_y generated by yy (cf. Exercise 6).

(b) If y,z∈Mxy, z \in M_x, we write y∘z=fy(z)y \circ z = f_y(z). Show that the law of composition (y,z)↦y∘z(y, z) \mapsto y \circ z makes MxM_x into a monoid with identity element xx which is isomorphic to the monoid End(Mx)\mathrm{End}(M_x) of endomorphisms of MxM_x.

(c) Let NN be the set of monogenous submagmas of MxM_x distinct from MxM_x. An element yy of MxM_x is called primitive if MyM_y is a maximal element of NN. Show that xx,x(x(xx))xx, x(x(xx)) are primitive whereas x,(xx)(xx)x, (xx)(xx) are not.

(d) Let PP be the set of primitive elements of MxM_x. Show that, if y,z∈P,y≠zy, z \in P, y \neq z, then My∩Mz=∅M_y \cap M_z = \varnothing (use Exercise 6).

(e) Let Mo(P)\mathrm{Mo}(P) be the free monoid constructed on PP. If MxM_x is given the monoid structure defined in (b), the injection P→MxP \to M_x can be extended to a homomorphism p:Mo(P)→Mxp : \mathrm{Mo}(P) \to M_x. Show that pp is an isomorphism.

(If z∈Mxz \in M_x, show by induction on l(z)l(z) that z∈Im(p)z \in \mathrm{Im}(p). On the other hand, if y1,…,yn,z1,…,zm∈Py_1, \ldots, y_n, z_1, \ldots, z_m \in P are such that p(y1…yn)=p(z1…zm)p(y_1 \ldots y_n) = p(z_1 \ldots z_m), then My1∩Mz1≠∅M_{y_1} \cap M_{z_1} \neq \varnothing, whence y1=z1y_1 = z_1 and fy1(p(y2…yn))=fy1(p(z2…zm))f_{y_1}(p(y_2 \ldots y_n)) = f_{y_1}(p(z_2 \ldots z_m)); whence p(y2…yn)=p(z2…zm)p(y_2 \ldots y_n) = p(z_2 \ldots z_m) and it follows that y1…yn=z1…zmy_1 \ldots y_n = z_1 \ldots z_m arguing by induction on sup⁡(n,m)\sup(n, m).)

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