Exercise 15, § 8
Algebra, I, 173
A ringoid is a set with two laws of composition: (a) an associative multiplication ; (b) a law written additively, not everywhere defined (§ 1, no. 1) and satisfying the following conditions:
(1) it is commutative (in other words, if is defined, so is and ; and are then said to be addible);
(2) if and are addible, for and to be addible it suffices that and on the one hand, and and on the other, be addible; then and are addible and ;
(3) there exists an identity element 0;
(4) if and on the one hand, and on the other, are addible and , then ;
(5) if are addible, so are and (resp. and ) and
Every ring is a ringoid.
(a) Examine how the definitions and results of § 8 and the above exercises extend to ringoids (a left ideal of a ringoid is a subset of which is stable under addition and such that ).
(b) Let be a group with operators and and two endomorphisms of . For the mapping to be an endomorphism of , it is necessary and sufficient that every element of the subgroup be permutable with every element of ; if this endomorphism is then denoted by and is the composite endomorphism , show that the set of endomorphisms of with these laws of composition is a ringoid with unit element; for to be a ring, it is necessary and sufficient that be commutative.
For an element to be addible to all the elements of , it is necessary and sufficient that be contained in the centre of ; the set of these endomorphisms is a pseudo-ring called the kernel of the ringoid .
An endomorphism of is called normal if it is permutable with all the inner automorphisms of ; for every normal stable subgroup of , is then a normal stable subgroup of . Show that the set of normal endomorphisms of forms a subringoid of and that the kernel is a two-sided ideal in .†
Solution
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