Bourbaki

Exercise 3, § 8

Algebra, I, 172

Let A be a ring and a∈Aa \in A. If there exists one and only one a′∈Aa' \in A such that aa′=1aa' = 1, aa is invertible and a′=a−1a' = a^{-1} (show first that aa is left cancellable, then consider the product aa′aaa'a).

Solution

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Transcribed from the printed volume. Not translated.