Bourbaki

Exercise 21, § 1

Algebra, II, 385

Let A be a ring, b,cb, c two elements of A which are not right divisors of 0, M the A-module A/AbcA/Abc and N the submodule Ac/AbcAc/Abc of M. For N to be a direct factor in M, it is necessary and sufficient that there exist two elements x,yx, y of A such that xb+cy=1xb + cy = 1. (If ε\varepsilon is the class of 1 in M, show that a supplementary subspace of N in M is generated by an element of the form (1−yc)ε(1 - yc)\varepsilon whose annihilator is the ideal AcAc.)

Solution

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Transcribed from the printed volume. Not translated.