Bourbaki

Exercise 4, § 1

Algebra, II, 381

Let E, F1,F2F_1, F_2 be three A-modules and f1:F1→E,f2:F2→Ef_1 : F_1 \to E, f_2 : F_2 \to E two A-linear mappings. The fibre product of F1F_1 and F2F_2 relative to f1f_1 and f2f_2 is the submodule of the product F1×F2F_1 \times F_2 consisting of the ordered pairs (x1,x2)(x_1, x_2) such that f1(x1)=f2(x2)f_1(x_1) = f_2(x_2); it is denoted by F1×EF2F_1 \times_E F_2.

(a) For every ordered pair of A-linear mappings u1:G→F1,u2:G→F2u_1 : G \to F_1, u_2 : G \to F_2 such that f1∘u1=f2∘u2f_1 \circ u_1 = f_2 \circ u_2, there exists one and only one A-linear mapping u:G→F1×EF2u : G \to F_1 \times_E F_2 such that p1∘u=u1,p2∘u=u2p_1 \circ u = u_1, p_2 \circ u = u_2, where p1p_1 and p2p_2 denote the restrictions to F1×EF2F_1 \times_E F_2 of the projections pr_1 and pr_2.

(b) Let E′,F1′,F2′E', F'_1, F'_2 be three A-modules, f1′:F1′→E′,f2′:F2′→E′f'_1 : F'_1 \to E', f'_2 : F'_2 \to E' A-linear mappings and F1′×E′F2′F'_1 \times_{E'} F'_2 the fibre product relative to these mappings. For every system of A-linear mappings v1:F1→F1′,v2:F2→F2′,w:E→E′v_1 : F_1 \to F'_1, v_2 : F_2 \to F'_2, w : E \to E' such that f1′∘v1=w∘f1,f2′∘v2=w∘f2f'_1 \circ v_1 = w \circ f_1, f'_2 \circ v_2 = w \circ f_2, let vv be the A-linear mapping of F1×EF2F_1 \times_E F_2 into F1′×E′F2′F'_1 \times_{E'} F'_2 corresponding to the two linear mappings v1∘p1v_1 \circ p_1 and v2∘p2v_2 \circ p_2. Show that if v1v_1 and v2v_2 are injective, so is vv; give an example where v1v_1 and v2v_2 are surjective but vv is not surjective (take E′={0}E' = \{0\}). If ww is injective and v1v_1 and v2v_2 surjective, show that vv is surjective.

Solution

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Transcribed from the printed volume. Not translated.