Bourbaki

Exercise 1, § 10

Algebra, II, 417

(a) Let EE be a right AA-module. On the additive group ErE^r (with r≥1r \geq 1) an external law of composition is defined with Mr(A)\mathbf{M}_r(A) as set of operators, denoting by x.Px.P, for every element x=(xi)1≤i≤rx = (x_i)_{1 \leq i \leq r} of ErE^r and every square matrix P=(αij)∈Mr(A)P = (\alpha_{ij}) \in \mathbf{M}_r(A), the element y=(yi)y = (y_i) of ErE^r such that

yi=∑j=1rxjαji(1≤i≤r). y_i = \sum_{j=1}^r x_j \alpha_{ji} \qquad (1 \leq i \leq r).
This external law defines with the additive law on ErE^r a right Mr(A)\mathbf{M}_r(A)-module structure on ErE^r; by restricting the ring of operators of the ring of scalar matrices I.αI.\alpha, the product AA-module structure on ErE^r is recovered. Show that for the AA-module EE to have a generating system of rr elements, it is necessary and sufficient that the Mr(A)\mathbf{M}_r(A)-module ErE^r be monogenous.

(b) Let (xi)1≤i≤n(x_i)_{1 \leq i \leq n} be a generating system of EE and (yj)1≤j≤m(y_j)_{1 \leq j \leq m} a family of elements of EE (resp. a generating system of EE). Let z,z′,z′′z, z', z'' be three elements of Em+nE^{m+n} such that zi=xiz_i = x_i for 1≤i≤n1 \leq i \leq n, zn+j=0z_{n+j} = 0 for 1≤j≤m1 \leq j \leq m, zi′=xiz'_i = x_i for 1 ≤i≤n, zn+j′=yj\leq i \leq n,\ z'_{n+j} = y_j for 1≤j≤n, zi′′=01 \leq j \leq n,\ z''_i = 0 for 1≤i≤n, zn+j′′=yj1 \leq i \leq n,\ z''_{n+j} = y_j for 1≤j≤n1 \leq j \leq n. Show that there exist two invertible matrices P,QP, Q of Mn+m(A)\mathbf{M}_{n+m}(\mathbf{A}) such that z′=z.Pz' = z.P (resp. z′′=z.Qz'' = z.Q).

(c) If A\mathbf{A} is commutative, uP:x↦x.Pu_P : x \mapsto x.P is an endomorphism of the A\mathbf{A}-module E′E' and the mapping P↦uPP \mapsto u_P is a homomorphism of the ring Mr(A)\mathbf{M}_r(\mathbf{A}) into the ring End⁡A(E′)\operatorname{End}_\mathbf{A}(E'). If EE is a faithful A\mathbf{A}-module this homomorphism is injective.

Solution

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Transcribed from the printed volume. Not translated.