Bourbaki

Exercise 23, § 2

Algebra, II, 394

Bourbaki marks this one as harder than the rest.

Let M be an A-module, the direct sum of a family (finite or otherwise) (Mλ)λ∈L(M_\lambda)_{\lambda \in L} of submodules such that for all λ∈L\lambda \in L the non-invertible elements of End⁡(Mλ)\operatorname{End}(M_\lambda) form a two-sided ideal of this ring (which implies that MλM_\lambda is indecomposable).

(a) Let f,gf, g be two endomorphisms of MM such that f+g=1Mf + g = 1_M. Show that for every finite sequence (λk)1≤k≤s(\lambda_k)_{1 \leq k \leq s} of distinct indices in LL there exists a family of submodules NkN_k (1≤k≤s)(1 \leq k \leq s) of MM such that for every kk one of the endomorphisms f,gf, g restricted to MλkM_{\lambda_k} is an isomorphism of this submodule onto NkN_k and that MM is the direct sum of the NkN_k (1≤k≤s)(1 \leq k \leq s) and the MλM_\lambda for λ\lambda distinct from λk\lambda_k. (Reduce it to the case s=1s = 1; if πλ\pi_\lambda is the canonical projection of MM onto MλM_\lambda corresponding to the decomposition as a direct sum of MλM_\lambda and ⨁μ≠λMμ\bigoplus_{\mu \neq \lambda} M_\mu, note that either πλ∘f\pi_\lambda \circ f or πλ∘g\pi_\lambda \circ g, restricted to MλM_\lambda, is an automorphism of MλM_\lambda.)

(b) Let ff be an idempotent endomorphism of MM. Show that there exists at least one index λ∈L\lambda \in L such that the restriction of ff to MλM_\lambda is an isomorphism of MλM_\lambda onto f(Mλ)f(M_\lambda); moreover f(Mλ)f(M_\lambda) is a direct factor of MM. (If g=1M−fg = 1_M - f, note that there exists a finite sequence of indices (λk)1≤k≤s(\lambda_k)_{1 \leq k \leq s} such that the intersection of Ker⁡(g)\operatorname{Ker}(g) and the direct sum of the MλkM_{\lambda_k} is ≠{0}\neq \{0\} and use (a).)

(c) Deduce from (b) that every indecomposable direct factor of MM is isomorphic to one of the MλM_\lambda.

(d) Let (Nκ)κ∈K(N_\kappa)_{\kappa \in K} be a family of indecomposable submodules of MM of which MM is the direct sum; every NκN_\kappa is therefore isomorphic to an MλM_\lambda and vice versa, by virtue of (c). Let TT be the set of classes of indecomposable submodules of MM (under the relation of isomorphism) such that an MλM_\lambda (or an NκN_\kappa) belongs to one of these classes. For all t∈Tt \in T, let R(t)R(t) (resp. S(t)S(t)) be the set of λ∈L\lambda \in L (resp. κ∈K\kappa \in K) such that Mλ∈tM_\lambda \in t (resp. Nκ∈tN_\kappa \in t). Show that, for all t∈Tt \in T, Card⁡(R(t))=Card⁡(S(t))\operatorname{Card}(R(t)) = \operatorname{Card}(S(t)). (In the notation of (a), let J(κ)J(\kappa) be the set λ∈L\lambda \in L such that the restriction of πλ\pi_\lambda to NκN_\kappa is an isomorphism of NκN_\kappa onto MλM_\lambda; show that J(κ)J(\kappa) is finite and that the J(κ)J(\kappa) cover R(t)R(t) when κ\kappa runs through S(t)S(t). Deduce that Card⁡(S(t))≤Card⁡(R(t))\operatorname{Card}(S(t)) \leq \operatorname{Card}(R(t)) when R(t)R(t) is infinite. When R(t)R(t) is finite, show with the aid of (a) that MM is the direct sum of the MλM_\lambda for λ∉R(t)\lambda \notin R(t) and a subfamily of (Nκ)κ∈S(t)(N_\kappa)_{\kappa \in S(t)} of cardinal equal to that of R(t)R(t).)

(e) Deduce from (d) and Exercises 22 and 21 (d) that if (Eλ)λ∈L(E_\lambda)_{\lambda \in L} and (Eκ′)κ∈K(E'_\kappa)_{\kappa \in K} are two reduced irreducible decompositions of {0}\{0\} in a module FF, LL and KK are equipotent.

Solution

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Transcribed from the printed volume. Not translated.