Bourbaki

Exercise 26, § 2

Algebra, II, 395

For every Z\mathbf{Z}-module GG and every integer n>0n > 0, let nG_n G denote the kernel of the endomorphism x↦nxx \mapsto nx of GG. If 0→G′→G→G′′→00 \to G' \to G \to G'' \to 0 is an exact sequence, define a canonical homomorphism d:nG′′→G′/nG′d : _n G'' \to G'/nG' such that the sequence

0⟶nG′⟶nG′′→dG′/nG′⟶G/nG⟶G′′/nG′′⟶0 0 \longrightarrow _n G' \longrightarrow _n G'' \xrightarrow{d} G'/nG' \longrightarrow G/nG \longrightarrow G''/nG'' \longrightarrow 0

is exact. If nG_n G and G/nGG/nG are finite, we write

hn(G)=Card⁡(G/nG)−Card⁡(nG); h_n(G) = \operatorname{Card}(G/nG) - \operatorname{Card}(_n G);

then show that nG′_n G', nG′′_n G'', G′/nG′G'/nG', G′′/nG′′G''/nG'' are finite and that

hn(G)=hn(G′)+hn(G′′). h_n(G) = h_n(G') + h_n(G'').
Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.