Bourbaki

Exercise 4, § 2

Algebra, II, 387

Bourbaki marks this one as harder than the rest.

(a) Let E, E' be two A-modules, N a submodule of E and N' a submodule of E' such that E is projective and E/N and E'/N' are isomorphic. Show that there exists an exact sequence

0⟶N→uE⊕N′→vE′⟶0. 0 \longrightarrow N \xrightarrow{u} E \oplus N' \xrightarrow{v} E' \longrightarrow 0.

(Observe that there exists a homomorphism f:E→E′f : E \to E' such that f(N)⊂N′f(N) \subset N', which gives when passing to the quotients an isomorphism E/N→E′/N′E/N \to E'/N'; define u and v in an analogous way to that used for the exact sequence (29) of § 1, no. 7.)

(b) Deduce from (a) that if E' is projective, E⊕N′E \oplus N' and E′⊕NE' \oplus N are isomorphic.

(c) Let 0→Em→Em−1→…→E1→E0→00 \to E_m \to E_{m-1} \to \ldots \to E_1 \to E_0 \to 0 be an exact sequence of A-modules such that E0,E1,…,Em−2E_0, E_1, \ldots, E_{m-2} are projective. Show that the A-modules ⨁h≥0Em−2h\bigoplus_{h \geq 0} E_{m-2h} and ⨁h≥0Em−2h+1\bigoplus_{h \geq 0} E_{m-2h+1} are isomorphic (with the convention that Ei={0}E_i = \{0\} for i<0i < 0).

Solution

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Transcribed from the printed volume. Not translated.