Bourbaki

Exercise 1, § 4

Algebra, II, 396

Let A,BA, B be two rings, EE a left AA-module, FF a right AA-module and GG an (A,B)(A, B)-bimodule; HomB(F,G)\mathrm{Hom}_B(F, G) then has a left AA-module structure and HomA(E,G)\mathrm{Hom}_A(E, G) a right BB-module structure. Show that the Z\mathbf{Z}-modules

HomA(E,HomB(F,G))andHomB(F,HomA(E,G)) \mathrm{Hom}_A(E, \mathrm{Hom}_B(F, G)) \quad \text{and} \quad \mathrm{Hom}_B(F, \mathrm{Hom}_A(E, G))
are both canonically isomorphic to the Z\mathbf{Z}-module of Z\mathbf{Z}-bilinear mappings ff of E×FE \times F into GG such that f(αx,y)=αf(x,y)f(\alpha x, y) = \alpha f(x, y) and f(x,yβ)=f(x,y)βf(x, y\beta) = f(x, y)\beta for α∈A,β∈B,x∈E,y∈F\alpha \in A, \beta \in B, x \in E, y \in F.

Solution

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Transcribed from the printed volume. Not translated.