Exercise 11, § 11
Algebra, III, 649
Bourbaki marks this one as harder than the rest.
Let be an identity between minors of an invertible square matrix of order over a commutative ring , the complementary identity (Exercise 10) and an integer . Let be an invertible square matrix of order and let be the submatrix of the adjoint matrix formed by suppressing in the rows of index and the columns of index . If is assumed to be invertible and the identity is applied to the minors of and then each minor which appears in this identity (considered as a minor of ) is replaced by its expression as a function of the minors of , using identity (1) of Exercise 9, an identity is obtained between minors of the matrix (valid if and are invertible) which is called the extension of order of the identity .
In particular, Let be an invertible square matrix of order , the submatrix of of order obtained by suppressing in the rows and columns of index and the determinant of the matrix of order obtained by suppressing in the rows of index except that of index and the columns of index except that of index ; if denotes the matrix of order , show the identity
State the identities obtained by extending the Laplace expansion (§ 8, no. 6) and the identity of Exercise 2 of § 8.
Solution
No solution has been written yet.