Bourbaki

Exercise 17, § 8

Algebra, III, 641

Let

(*)

∑j=1nαijξj=βi(1≤i≤m) \sum_{j=1}^n \alpha_{ij} \xi_j = \beta_i \quad (1 \leq i \leq m)

be a system of mm linear equations in nn unknowns over a commutative ring A\mathbf{A}. Let xjx_j (1≤j≤n1 \leq j \leq n) be the columns of the matrix X=(αij)X = (\alpha_{ij}) of this system and y=(βi)y = (\beta_i); suppose that in XX all the minors of order >p> p are zero but that x1∧x2∧⋯∧xp≠0x_1 \wedge x_2 \wedge \cdots \wedge x_p \neq 0. For the system (*) to have a solution, it is necessary that x1∧x2∧⋯∧xp∧y=0x_1 \wedge x_2 \wedge \cdots \wedge x_p \wedge y = 0. Conversely, if this condition holds, there exist n+1n + 1 elements ξj\xi_j (1≤j≤n+11 \leq j \leq n + 1) of A\mathbf{A} such that ξn+1≠0\xi_{n+1} \neq 0 and

∑j=1nαijξj=βiξn+1(1≤i≤m). \sum_{j=1}^n \alpha_{ij} \xi_j = \beta_i \xi_{n+1} \quad (1 \leq i \leq m).
Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.