Bourbaki marks this one as harder than the rest.
Let K be an infinite commutative field, m,n,r three integers ≥0 such that r≤n≤m, Mm,n(K) the vector K-space (of dimension mn) consisting of the matrices of type (m,n) over K and V a vector subspace of Mm,n(K) such that r is the greatest value of the rank of matrices X∈V. We propose to prove the inequality
(*) dim(V)≤mr.
(a) Show that we can assume that m=n and that the matrix
X0=(Ir000)
belongs to V. Deduce that every matrix X∈V is then of the form
(X11X21X120)
(where X11 is of order r) with the condition X21X12=0 (use the fact that for all ξ∈K, the matrix ξX0+X is of rank ≤r).
(b) Deduce from (a) that, for two matrices X,Y in V,
X21Y12+Y21X12=0.
(c) For every matrix X∈V, we write F(X)=(X11X12)∈Mr,n(K);f is a linear mapping and dim(V)=dim(Im(f))+dim(Ker(f)). On the other hand, let ux denote the linear form (Y11Y12)↦Tr(X21Y12) on Mr,n(K). Show that the linear mapping X↦uX of Ker(f) into the dual (Mr,n(K))∗ is injective; complete the proof of (*) by noting that the image under X↦uX of Ker(f) is contained in the orthogonal of Im(f).