Bourbaki

Exercise 1, § 9

Algebra, III, 644

Let KK be a commutative field with at least 3 elements and AA the algebra over KK with a basis consisting of the unit element 1 and two elements e1,e2e_1, e_2 such that e12=e1,e1e2=e2,e2e1=e22=0e_1^2 = e_1, e_1 e_2 = e_2, e_2 e_1 = e_2^2 = 0; let A0A^0 be the opposite algebra to AA. Show that there exists in AA elements xx such that Tr⁡A/K(x)≠Tr⁡A0/K(x)\operatorname{Tr}_{A/K}(x) \neq \operatorname{Tr}_{A^0/K}(x) and NA/K(x)≠NA0/K(x)N_{A/K}(x) \neq N_{A^0/K}(x).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.