Bourbaki

Exercise 9, § 6

Algebra, IV, p. 100

a) Let K be a field and X1,…,XnX_1, \ldots, X_n indeterminates. Show that for any exponents v1<v2<…<vnv_1 < v_2 < \ldots < v_n the determinant det⁡(Xivj)\det(X_i^{v_j}) is non-zero in K(X1,…,Xn)K(X_1, \ldots, X_n).

b) Let sks_k (1≤k≤n1 \leq k \leq n) be the elementary symmetric polynomials in the XiX_i and r1,…,rnr_1, \ldots, r_n n elements of the field K(X1,…,Xn)K(X_1, \ldots, X_n). We put (with a new indeterminate T)

R(T)=1+r1T+⋯+rnTn1+s1T+⋯+snTn=1+u1T+⋯+ukTk+⋯ . R(T) = \frac{1 + r_1 T + \cdots + r_n T^n}{1 + s_1 T + \cdots + s_n T^n} = 1 + u_1 T + \cdots + u_k T^k + \cdots.

Show that if nn of the coefficients uku_k are zero, then all the uku_k are zero. (Decompose R(T)R(T) into simple fractions.)

*c) Suppose that K is of characteristic zero. Let {v1,v2,…,vn}\{v_1, v_2, \ldots, v_n\} be a set of n elements ≥1\geq 1 of N\mathbf{N}, and let M be the complement of this set in N\mathbf{N}; suppose also that M is stable under addition. Show that if y1,…,yny_1, \ldots, y_n are n elements of K(X1,…,Xn)K(X_1, \ldots, X_n) such that

Pvj(y1,…,yn)=Pvj(X1,…,Xn) P_{v_j}(y_1, \ldots, y_n) = P_{v_j}(X_1, \ldots, X_n)

for 1≤j≤n1 \leq j \leq n, then yj=Xjy_j = X_j for 1≤j≤n1 \leq j \leq n except possibly for a permutation. (Consider the expansion of log⁡R(T)=v1T+v2T2+⋯+vkTk+⋯\log R(T) = v_1 T + v_2 T^2 + \cdots + v_k T^k + \cdots, observe that vvj=0v_{v_j} = 0 for 1≤j≤n1 \leq j \leq n and examine the relations between the vkv_k and the uku_k.)

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.