Algebra, V, p. 160
Let k be a field of characteristic 2. a) Let A1,…,An be indeterminates, K the field k(A1,...,An), E a splitting field of the polynomial P=Xn+A1Xn−1+...+An∈K[X] and X1,...,Xn the roots of P in E, so that E=k(X1,...,Xn) (V, p. 21). We identify the Galois group of E/K with the symmetric group Sn acting by permutations of the variables X1,...,Xn (V, p. 59). Put
β(X1,...,Xn)=i<j∑Xi/(Xi+Xj)∈EandC(A1,...,An)=i<j∑(XiXj)/(Xi2+Xj2)∈K. Then
β∈/K and
β2+β+C=0. We have
σ(β)=β for
σ∈Un and
σ(β)=β+1 for
σ∈Sn−Un. Deduce that
K(β) is the unique quadratic subextension of
E/K. b) Let
D∈Z[T1,...,Tn] be the discriminant of the polynomial
Xn+T1Xn−1+...+Tn. Show that there exist Q, R, S
∈Z[T1,...,Tn] with
D=Q2−4R+8S and
C=C(A1,...,An)=Q2(A1,...,An)R(A1,...,An)=D(A1,...,An)R(A1,...,An). For every triple of elements U, V, W of
Z[T1,...,Tn] such that
D=U2−4V+8W there exists
M∈Z[A1,...,An] such that
C=D(A1,...,An)V(A1,...,An)+(D(A1,...,An)M)2+D(A1,...,An)M c) Let
f=Xn+a1Xn−1+...+an be a separable polynomial of
k[X] and G the Galois group of a splitting extension. Show that
(a1,...,an) is substitutable in C and that the following conditions are equivalent (i) every element of G induces an even permutation of the roots of f ; (ii) there exists
a∈k such that
C(a1,...,an)=a2+a. \* d) Henceforth assume that k is finite and choose the elements U, V, W of
Z[T1,...,Tn] arbitrarily to satisfy the condition stated in b). Show that (i) and (ii) of c) are equivalent to the following conditions : (iii)
Trk/F2(C)=0; (iv)
Trk/F2(D(a1,...,an)V(a1,...,an))=0. (v) The number of irreducible factors of f is congruent to n modulo 2 (use Ex. 22 of V, p. 165). \*