Exercise 12, § 11
Algebra, V, p. 163
Let K be a field of characteristic q, an algebraically closed extension of K, x an element of such that and M a maximal element of the set of subextensions of not containing x (V, p. 156, Ex. 9); suppose further that M is perfect so that is a Galois extension of prime degree p of M (loc. cit.). a) Show that either and or for each integer r , there exists a single extension of degree of M; this extension M, is cyclic over M, is the union of the M, and the M, are the only extensions of finite degree of M. (Note that if a p-group of order has only one subgroup of order , it is necessarily cyclic, arguing by induction on r and using I, p. 133, Ex. 10, and I, p. 77, Cor. of Prop. 11). b) Suppose that and that . Show that M contains the p-th roots of unity; we thus have with . Show that if a is the p-th power of an element of , then , where is -th root of unity (if for , consider the minimal polynomial of in ). c) Under the hypotheses of b) show that if a is not a p-th power of an element of then is the splitting field of the polynomial of (use b)). d) Under the hypotheses of b), show that if a is the p-th power of an element of , there exists such that and that is the splitting field of ; show that y is not the p-th power of an element of and deduce that is the splitting field of the polynomial of .
Solution
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