Exercise 1, § 1
Algebra, VI
A not necessarily commutative ordered monoid M is a (multiplicatively written) monoid equipped with an ordering such that the relation x ≤ y implies zx ≤ zy and xz ≤ yz for all z ∈ M. Let G be a not necessarily commutative ordered group. Show that: a) If P denotes the set of elements greater than the identity e of G, then P . P = P, P ∩ P and for all a ∈ G. Prove the converse. Find a condition for G to be totally ordered. b) If one of the elements sup(x, y), inf(x, y) exists, then so does the other, and
c) The elements sup(x, e) and sup(, e) commute. Two coprime elements commute. d) The subgroup G' generated by the irreducible elements of G is commutative. Deduce that Th. 2 of VI, p. 18 is still valid.
Solution
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