Bourbaki

Exercise 20, § 1

Algebra, VI, p. 32

Bourbaki marks this one as harder than the rest.

Let GG be an additive group and let PP be a subset of GG satisfying the following conditions: 1. P+P=PP + P = P; 2. P∩(−P)=(0)P \cap (-P) = (0); 3. for every integer n>0n > 0, nx∈Pnx \in P implies x∈Px \in P (conditions (C)).

EXERCISES

a) If a is an element of G such that a ∉P\notin P, show that there exists a subset P' of G, satisfying conditions (C'), such that P⊂P′P \subset P' and −a∈P′-a \in P' (take P' to be the set of x∈Gx \in G such that there exist integers m>0m > 0 and n≥0n \geq 0 and an element y∈Py \in P with mx=−na+ymx = -na + y.

b) Deduce from a) that P is the intersection of those subsets T of G such that T+T=T,T∩(−T)={0},T∪(−T)=GT + T = T, T \cap (-T) = \{0\}, T \cup (-T) = G (that is, making G a totally ordered group) and P⊂TP \subset T (use Zorn's Lemma).

c) In particular if G is an additive group in which every nonzero element has infinite order, then the intersection of all the subsets T of G such that T+T=T,T∩(−T)=(0)T + T = T, T \cap (-T) = (0) and T∪(−T)=GT \cup (-T) = G is {0}\{0\}.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.