Bourbaki

Exercise 8, § 4

Algebra, VII, p. 64

Let G be a module of finite length over a principal ideal domain A. For any pair of free modules M and N such that N⊂MN \subset M and G is isomorphic to M/NM/N, the invariant factors of N with respect to M which are distinct from A are identical to the invariant factors of G (VII, p. 20, Def. 2); their number is called the rank of G.

a) Show that the rank rr of G is the least number of cyclic submodules of G of which G is the direct sum, and is equal to the greatest of the ranks of the π\pi-primary components of G.

b) Show that the rank of a submodule or a quotient module of G is at most equal to the rank of G (consider G as a quotient of two free modules of rank r).

c) For each A∈AA \in A, show that the rank of the submodule AG is equal to the number of invariant factors of G which do not divide A (notice that, if E=A/(Aα)E = A/(A\alpha), then the module λE\lambda E is isomorphic to (Aλ)/((Aα)∩(Aλ))(A\lambda)/((A\alpha) \cap (A\lambda))). Deduce that the k-th invariant factor of G (in decreasing order) is a gcd of those A∈AA \in A such that AG has rank ≤r−k\leq r - k.

d) Let AαkA\alpha_k (1≤k≤r1 \leq k \leq r) be the invariant factors of G arranged in decreasing order. Let H be a submodule of G of rank r−qr - q, and let AβkA\beta_k (1≤k≤r−q1 \leq k \leq r - q) be its invariant factors, arranged in decreasing order. Deduce from b) and c) that βk\beta_k divides αk−q\alpha_{k-q} for 1≤k≤r−q1 \leq k \leq r - q. Similarly show that, if G/HG/H has rank r−pr - p and invariant factors Ay,(1≤k≤r−p)Ay, (1 \leq k \leq r - p) in decreasing order, then γk\gamma_k divides ar−pa_{r-p} for 1≤k≤r−p1 \leq k \leq r - p.

e) Conversely, let L be a torsion module of rank r−qr - q, whose invariant factors AλkA\lambda_k (1≤k≤r−q1 \leq k \leq r - q) are such that λk\lambda_k divides αk+q\alpha_{k+q} for 1≤k≤r−q1 \leq k \leq r - q. Show that there exist submodules M and N of G such that L is isomorphic to M and to G/N (decompose G into a direct sum of submodules isomorphic to A/AαkA/A\alpha_k).

Solution

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Transcribed from the printed volume. Not translated.