Exercise 11, § 14
Tag 00HM, permanent. Cite it as [Bourbaki, Tag 00HM].
Algebra, VIII, p. 271
Bourbaki marks this one as harder than the rest.
Let A be a commutative integral domain, K its field of fractions, and S an Azumaya A-algebra (Exercise 8).
a) Prove that the K-algebra is central simple. Identify S with a subalgebra of . b) Assume from now on that A is the only A-subalgebra of K that is a finitely generated A-module, that is, that the ring A is integrally closed, cf. Comm. Alg., V,
§1, No. . Prove that S is maximal (for the inclusion) among the A-subalgebras of that are finitely generated as A-modules (apply Exercise 9, d)).
c) Suppose, moreover, that A is Noetherian and that the K-algebra is isomorphic to End(V), where V is a vector space over K. Prove that there exists a finitely generated A-module M without torsion such that the A-algebra S is isomorphic to End (let be a nonzero vector of V; take M to be the set of elements as runs through S).
d) Prove that in the previous construction, we may assume M reflexive (replace M
with its bidual). If, moreover, the ring A is regular (AC, X, §4, n, p. 55, définition 1), then the A-module M is projective (apply AC, X, §4, p. 164, exercice )
Solution
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Cites
- AC, X, §4, n$^o2$, p. 55 not in this corpus: AC X
- AC, X, §4, p. 164 not in this corpus: AC X
- Exercise 8
- Exercise 9