Bourbaki

Exercise 11, § 6

Tag 03NR, permanent. Cite it as [Bourbaki, Tag 03NR].

Theory of Sets, III, 242

Bourbaki marks this one as harder than the rest.

(a) Show that the ordinal ω\omega is the least ordinal >0> 0 which has no predecessor, that ω\omega is indecomposable (§ 2, Exercise 16), and that for each ordinal α>0\alpha > 0, αω\alpha\omega is the least indecomposable ordinal which is >α> \alpha (note that nω=ωn\omega = \omega for each integer nn). Deduce that

(α+1)ω=αωfor each α>0.(\alpha + 1)\omega = \alpha\omega \quad \text{for each } \alpha > 0.

(b) Deduce from (a) that an ordinal is indecomposable if and only if it is of the form ωβ\omega^\beta (use Exercise 18 (d) of § 2).

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Transcribed from the printed volume. Not translated.