Bourbaki

Exercise 7, § 1

Topological Vector Spaces, I, p. 23

\* Let A be a ring with a discrete valuation, v the normed valuation of the division ring of fractions K of A; take the absolute value ava^v on K, where 0<a<10 < a < 1. Let E be a normed vector space over K, for which the norm satisfies the ultrametric inequality

∥x+y∥≤sup⁡(∥x∥,∥y∥). \|x + y\| \leq \sup(\|x\|, \|y\|).

a) Denote by M the set of those x∈Ex \in E for which ∥x∥≤1\|x\| \leq 1, and by π\pi a uniformizer of A; M is an A-module, and M/πMM/\pi M a vector space on the residual division ring k=A/πAk = A/\pi A of A. Let (eλ)λ∈L(e_\lambda)_{\lambda \in L} be a family of elements of M such that the images of eλe_\lambda in M/πMM/\pi M form a basis of this vector k-space. Show that (eλ)(e_\lambda) is an independent family in E and that the vector subspace F of E generated by (eλ)(e_\lambda) is dense in E. b) If we put ∥x∥1=sup⁡λ∣ξλ∣\|x\|_1 = \sup_\lambda |\xi_\lambda|, for every x=∑λξλeλx = \sum_\lambda \xi_\lambda e_\lambda in F, show that on F the norms ∥x∥\|x\| and ∥x∥1\|x\|_1 are equivalent. c) Let K be complete. Deduce from a) and b) that, if L is finite, the completion E^\hat{E} of E is isomorphic to KLK^L; if L is infinite E^\hat{E} is isomorphic to the subspace CK0(L)\mathscr{C}_K^0(L) of BK(L)\mathscr{B}_K(L) formed of the families (ξλ)(\xi_\lambda) such that lim⁡ξλ=0\lim \xi_\lambda = 0 for the filter of complements of finite subsets of L. d) We suppose K and E complete; let G be a second normed complete space over K whose norm satisfies the ultrametric inequality. Show that on replacing (if necessary) the norm of L(E;G)\mathscr{L}(E; G) (GT, X, § 3.2) by an equivalent one, then L(E;G)\mathscr{L}(E; G) is isometric to the vector space of families (yλ)λ∈L(y_\lambda)_{\lambda \in L} of elements of G such that sup⁡λ∈L∥yλ∥<+∞\sup_{\lambda \in L} \|y_\lambda\| < + \infty, carrying the norm sup⁡λ∈L∥yλ∥\sup_{\lambda \in L} \|y_\lambda\| (which is also an ultrametric norm).

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Transcribed from the printed volume. Not translated.