Exercise 24, § 7
Topological Vector Spaces, II, p. 90
Bourbaki marks this one as harder than the rest.
In , every intersection of finitely many closed half spaces (resp. of closed half-spaces determined by hyperplanes passing through the same point) is called a polyhedron (resp. a polyhedral cone). A convex set is locally polyhedral in a point if there is a neighbourhood of in which is a polyhedron. *a) Show that, if a closed convex set is locally polyhedral at a point , then the cone with vertex generated by is polyhedral. *b) Show that a compact convex set in that is locally polyhedral at each of its points is a polyhedron (use a). *c) Let be a closed convex set with an interior point. Show that the following conditions are equivalent : α) is a polyhedron. β) has only a finite number of facets (II, p. 87, exerc. 3). γ) is the convex envelope of a set which is the union of finitely many points and finitely many closed half lines. (To show that implies ) take as the intersection of the smallest possible number of closed half spaces, and show that the hyperplanes defining these half-spaces are generated by facets of dimension of . To show that implies ), argue by induction on . Finally, to see that implies ), consider the polar of . *d) Show that every convex polyhedron can be written in the form , where is a compact polyhedron and the asymptotic cone of . A non compact polyhedron cannot be parabolic. *e) Show that every facet of a convex polyhedron is an ultrafacet (II, p. 88, exerc. 7, d)) (argue by induction on ).
Solution
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