Bourbaki

Exercise 12, § 4

Topological Vector Spaces, III, p. 44

It is set in small type as supplementary.

a) Let E be a locally convex space, (An)(A_n) an increasing sequence of convex balanced sets in E such that A=⋃nAnA = \bigcup_n A_n is absorbent. Let (Wn)(W_n) be a decreasing sequence of convex balanced neighbourhoods of 0; then the convex balanced envelope V of the Wn∩AnW_n \cap A_n is absorbent; if E is barrelled, V‾\overline{V} is a neighbourhood of 0. b) Let F\mathfrak{F} be a filter on E; suppose that for every n, there exists a set Mn∈FM_n \in \mathfrak{F} such that (Mn+Wn)∩A2n=∅(M_n + W_n) \cap A_{2n} = \varnothing. Let VnV_n be the convex balanced envelope of the Wk∩AkW_k \cap A_k for k≤n−1k \leq n - 1 and of WnW_n in such a way that VnV_n is a neighbourhood of 0 and that we have 12V‾⊂Vn\frac{1}{2} \overline{V} \subset V_n for all n. Show that (Mn+Vn)∩An=∅(M_n + V_n) \cap A_n = \varnothing for all n. c) Deduce from a) and b) that if E is barrelled and if F\mathfrak{F} is a Cauchy filter on E, then there exists an integer N such that, for all M∈FM \in \mathfrak{F} and every neighbourhood W of 0 in E, M+WM + W meets ANA_N. (Argue by contradiction; with the notations of b), consider a set M∈FM \in \mathfrak{F} with small order 12V‾\frac{1}{2} \overline{V}.)

Solution

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Transcribed from the printed volume. Not translated.