Bourbaki

Exercise 16, § 2

Topological Vector Spaces, IV, p. 54

Bourbaki marks this one as harder than the rest.

With the notations of exerc. 14, let E′′E'' be the dual of E′′=ℓ∞(A)E'' = \ell^\infty(A). a) Let eαe_\alpha (for α∈A\alpha \in A) be the element of E′′E'' for which eα(β)=δαβe_\alpha(\beta) = \delta_{\alpha \beta} (Kronecker's symbol). Let (Kn)(K_n) be a sequence of finite subsets of A, two by two disjoint, and let (xn′′′)(x'''_n) be a sequence of points in E′′′E'''. Show that there exists (nk)(n_k), a strictly increasing infinite sequence of integers >0> 0 such that, if we put B=⋃kKnkB = \bigcup_k K_{n_k}, then the elements yn′=(xn′′′(α))α∈By'_n = (x'''_n(\alpha))_{\alpha \in B} belong to ℓ1(B)\ell^1(B). (Let δ\delta be an arbitrary number >0> 0, and let (Jm)m∈N(J_m)_{m \in \mathbf{N}} be a partition of N\mathbf{N} in finite sets. Arguing by reductio ad absurdum, show that if x′′′∈E′′′x''' \in E''', then there exists an integer m such that ∣⟨x′′,x′′′⟩∣≤δ|\langle x'', x''' \rangle| \leq \delta for all x′′∈E′′x'' \in E'' for which ∥x′′∥≤1\|x''\| \leq 1 and x′′(α)=0x''(\alpha) = 0 except for indices α\alpha belonging to the set ⋃n∈JmKn\bigcup_{n \in J_m} K_n. Apply this result successively to x1′′′,x2′′′,...x'''_1, x'''_2, ... in a suitable way.) b) Deduce from a) and from exerc. 15, a) that, if (xn′′′)(x'''_n) is a sequence converging to 0 in E′′′E''' for the topology σ(E′′′,E′′)\sigma(E''' , E'') and if xn′′′~\tilde{x'''_n} is the restriction of xn′′′x'''_n to the strongly closed subspace E of E′′E'', then lim⁡n→∞∥xn′′′~∥=0\lim_{n \to \infty} \| \tilde{x'''_n} \| = 0 in E′E'.

c) Deduce from b) that, the strongly closed subspace E of E'' does not have a topological complement for the strong topology. (Restricting to the case A = N, let (en′)(e'_n) be the sequence of continuous linear forms on E such that ⟨x,en′⟩=x(n)\langle x, e'_n \rangle = x(n) for all x∈Ex \in E; show that the sequence (en′)(e'_n) tends to 0 for σ(E′,E)\sigma(E', E), but that en′e'_n cannot be extended to a continuous linear form xn′′′x'''_n on E′′E'' in such a way that the sequence (xn′′′)(x'''_n) tends to 0 for σ(E′′′′,E′′)\sigma(E'''', E'').)

Solution

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Transcribed from the printed volume. Not translated.