Bourbaki

Exercise 25, § 2

Topological Vector Spaces, IV, p. 57

Bourbaki marks this one as harder than the rest.

Let EE be a Banach space satisfying the first axiom of countability. Show that the following properties are equivalent : a) EE is not reflexive. b) For every number θ\theta such that 0<θ<10 < \theta < 1, there exists a sequence (xn′)(x'_n) in E′E' such that, ∥xn′∥≤1\|x'_n\| \leq 1 for all nn, that the sequence (xn′)(x'_n) converges to 0 for σ(E′,E)\sigma(E', E) and that the distance of 0 from the convex set generated by the xn′x'_n is ≥θ\geq \theta. c) For every number θ\theta such that 0<θ<10 < \theta < 1 and every sequence λn\lambda_n of numbers >0> 0 such that ∑nλn=1\sum_n \lambda_n = 1, there exists a number α\alpha such that θ≤α≤1\theta \leq \alpha \leq 1 and a sequence (yn′)(y'_n) of points of E′E' such that ∥yn′∥≤1\|y'_n\| \leq 1 for all nn, ∥∑nλnyn′∥=α\|\sum_n \lambda_n y'_n\| = \alpha and ∥∑k=1nλkyk′∥≤α(1−θ∑j=n+1∞λj)\left\| \sum_{k=1}^n \lambda_k y'_k \right\| \leq \alpha (1 - \theta \sum_{j=n+1}^\infty \lambda_j) for all nn. d) There exists z′∈E′z' \in E' such that for no x∈Ex \in E do we have ∣⟨x,z′⟩∣=∥x∥⋅∥z′∥|\langle x, z' \rangle| = \|x\| \cdot \|z'\| (Theorem of James-Klee). (To see that a) implies b), observe that there exists z′′∈E′′z'' \in E'' such that ∥z′′∥<1\|z''\| < 1 and d(z′′,E)>θd(z'', E) > \theta. If (xn)(x_n) is an everywhere dense sequence in EE, find the sequence (xn′)(x'_n) in E′E' such that ∥xn′∥<1\|x'_n\| < 1 and such that ⟨xk,xn′⟩=0\langle x_k, x'_n \rangle = 0 for k≤nk \leq n and ⟨xn′,z′′⟩=θ\langle x'_n, z'' \rangle = \theta. To see that b) implies c), use exerc. 24. For c) implies d), show that for all x∈Ex \in E we have ∣∑nλn⟨x,yn′⟩∣<α\left| \sum_n \lambda_n \langle x, y'_n \rangle \right| < \alpha, with the notations of c).

Solution

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