Exercise 6, § 2
Topological Vector Spaces, IV, p. 52
Bourbaki marks this one as harder than the rest.
Let and be two vector spaces in separating duality. a) Show that the following properties are equivalent : the space with a topology compatible with the duality between and , is semi-reflexive; the space , with , is barrelled. b) Show that the following properties are equivalent : the space , with , is reflexive;
β) the space G, with τ(G, F), is reflexive; γ) F and G are barrelled for τ(F, G) and τ(G, F) respectively. c) Show that every locally convex Hausdorff space E, with the topology τ(E, E') is isomorphic to the quotient of a semi-reflexive space F by a closed subspace. (By III, p. 44, exerc. 14, c), E' endowed with τ(E', E) is isomorphic to a closed vector subspace M of a Hausdorff barrelled space G; take F = G' endowed with τ(G', G) and use prop. 11 of IV, p. 10.) d) Let A be an infinite set with Card(A) > (S, III, § 6, exerc. 10). In the product space P = , let E_0 denote the everywhere dense subspace consisting of all x = such that except for a countable set of indices; the space E_0 is barrelled and so is the subspace E of P generated by E_0 and the point 1_A in P all whose coordinates are equal to 1 (III, p. 45, exerc. 16). Let B be a bounded subset in E_0, whose closure in P contains 1_A, and let J be a subset of A with cardinality ; let pr_J denote the projection from P onto ; show that there exists a subset B_J in B, with cardinality , such that the closure of pr_J(B_J) in contains 1_J; then the set J' ⊃ J of all indices such that for at least one point of B_J the coordinate with index is , has a cardinality equal to . We define J_0 = J and by induction , and put H = , whose cardinality is , and let ; show that the closure of (and hence also that of B) contains the point , which does not belong to E_0. Conclude that for every bounded and compact set C in E, C ∩ E_0 is again closed in E, and that E is not semi-reflexive. e) Deduce from d) that the dual E' of E (which can be identified with the dual P' = of P) is not complete for the topology τ(E', E), inspite of being semi-reflexive (hence quasi-complete) for this topology (consider the linear form on E which is equal to 0 on E_0 and equal to 1 at the point 1_A, and use III, p. 21, th. 2).
Solution
No solution has been written yet.