Bourbaki

Exercise 29, § 1

Topological Vector Spaces, V, p. 67

Bourbaki marks this one as harder than the rest.

Let E be a normed space, E' its dual. A mapping ff from E−{0}E - \{0\} into E′−{0}E' - \{0\} is said to be a support mapping if it is positively homogeneous, and if for every x∈Ex \in E such that ∥x∥=1\|x\| = 1, we have ∥f(x)∥=1\|f(x)\| = 1 and ⟨x,f(x)⟩=1\langle x, f(x) \rangle = 1. For E to be smooth (V, p. 66, exerc. 26), it is necessary and sufficient that there exists a unique support mapping from E−{0}E - \{0\} into E′−{0}E' - \{0\}.

Let S be the unit sphere in E, S' the unit sphere in E', and let x0∈Sx_0 \in S. The following conditions are equivalent : α) x0x_0 is a point of smoothness of the unit ball in E, β) There exists a support mapping ff whose restriction to S is continuous at the point x0x_0 when S is assigned the norm topology, and S' the weak topology σ(E′,E)\sigma(E', E). γ) For every y∈Ey \in E, the mapping t↦∥x0+ty∥t \mapsto \|x_0 + ty\| has a derivative at the point t=0t = 0. (To see that α) implies β), argue by reductio ad absurdum, using the weak compactness of the unit ball in E'. To see that β) implies γ), reduce to the case where E is 2-dimensional and use the fact that t↦∥x0+ty∥t \mapsto \|x_0 + ty\| is convex.) Then every support mapping is continuous at the point x0x_0.

Solution

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Transcribed from the printed volume. Not translated.