Bourbaki

Exercise 3, § 3

Functions of a Real Variable, II, 87

Let f(x,α)=1/1−2αx+α2f(x, \alpha) = 1/\sqrt{1 - 2\alpha x + \alpha^2} for −1<x<+1-1 < x < +1 and α∈R\alpha \in \mathbf{R}; show that the function g(α)=∫−1+1dx/1−2αx+α2g(\alpha) = \int_{-1}^{+1} dx/\sqrt{1 - 2\alpha x + \alpha^2} is continuous on R\mathbf{R}, but has no derivative at α=1\alpha = 1 and α=−1\alpha = -1; show that fα′(x,α)f'_\alpha(x, \alpha) exists for all α∈R\alpha \in \mathbf{R} and for x∈I=]−1,+1[x \in I = ]-1, +1[, and is continuous on I×RI \times \mathbf{R}, and that the integral ∫−1+1fα′(x,α) dx\int_{-1}^{+1} f'_\alpha(x, \alpha)\,dx exists for all α∈R\alpha \in \mathbf{R}, but verify that this integral is not uniformly convergent on a neighbourhood of the point α=1\alpha = 1 or of the point α=−1\alpha = -1.

Solution

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Transcribed from the printed volume. Not translated.