Exercise 3, § 2 Functions of a Real Variable, VI, 292 Show that, for every integer p>1p > 1p>1, Bn(xp)+Bn(x+1p)+⋯+Bn(x+p−1p)=1pn−1Bn(X). B_n \left( \frac{x}{p} \right) + B_n \left( \frac{x+1}{p} \right) + \cdots + B_n \left( \frac{x+p-1}{p} \right) = \frac{1}{p^{n-1}} B_n(X). Bn(px)+Bn(px+1)+⋯+Bn(px+p−1)=pn−11Bn(X). Solution No solution has been written yet.