Bourbaki

Chapter I

Inequalities of convexity

1. The fundamental inequality of convexity

Let X be a set; in the vector space RX\mathbf{R}^X of all finite numerical functions1^1 defined on X, let P be the set of all positive real-valued functions on X. On the other hand, let MM be a numerical function,2^2 finite or not, with values ⩾0\geqslant 0, defined on P, such that:

1∘1^\circ M(0)=0M(0) = 0, and MM is positively homogeneous, that is, M(λf)=λM(f)M(\lambda f) = \lambda M(f) for every real number λ>0\lambda > 0.3^3

2∘2^\circ MM is increasing in P, in other words the relation f⩽gf \leqslant g implies M(f)⩽M(g)M(f) \leqslant M(g).

3∘3^\circ MM is convex in P, in other words (TVS, II, §2, No. 8) satisfies the relation M(f+g)⩽M(f)+M(g)M(f + g) \leqslant M(f) + M(g).

Example. — Suppose X is a finite set, for example the interval [1,n][1, n] of N\mathbf{N}; denoting by xix_i (1⩽i⩽n1 \leqslant i \leqslant n) the coordinates of a vector x∈Rn\mathbf{x} \in \mathbf{R}^n, the functions

M1(x)=∑i=1nxiandM∞(x)=sup⁡1⩽i⩽nxi M_1(\mathbf{x}) = \sum_{i=1}^n x_i \quad \text{and} \quad M_\infty(\mathbf{x}) = \sup_{1 \leqslant i \leqslant n} x_i
satisfy the preceding conditions in the set P of vectors x\mathbf{x} with coordinates ⩾0\geqslant 0.

Remark. — Let S be a pointed convex cone contained in P (that is, a set such that S+S⊂SS + S \subset S and λS⊂S\lambda S \subset S for λ⩾0\lambda \geqslant 0; cf. TVS, II, §2, No. 4); let MM be a numerical function (finite or not) with values ⩾0\geqslant 0, defined on S and satisfying in S the above conditions 1∘,2∘1^\circ, 2^\circ and 3∘3^\circ. Then MM can be extended to the entire set P, in such a way that the extended function (which we denote again by MM) satisfies the same conditions: it suffices, for every function f∈Pf \in P, to set M(f)=+∞M(f) = +\infty if there does not exist any function g∈Sg \in S such that f⩽gf \leqslant g, and M(f)=inf⁡g∈S,f⩽gM(g)M(f) = \inf_{g \in S, f \leqslant g} M(g) in the contrary case. This procedure will be applied in Ch. IV, §1 to define the upper integral of a positive function.

(1) Fonction numérique finie—a function with values in R\mathbf{R}—may also be translated as "real-valued function" (cf. GT, IV, §5, No. 1).

(2) Fonction numérique—"numerical function"—signifies a function with values in R‾\overline{\mathbf{R}} (TG, IV, §5, No. 1). The phrase "finite or not" is sometimes added as a reminder that the function may take on infinite values.

(3) Recall that in R‾\overline{\mathbf{R}}, products such as 0⋅(+∞)0 \cdot (+\infty) are not defined (GT, IV, §4, No. 3).

PROPOSITION 1. — Let φ(t1,t2,…,tn)\varphi(t_1, t_2, \ldots, t_n) be a finite numerical function, defined and continuous for ti≥0t_i \geq 0 (1≤i≤n1 \leq i \leq n), such that: 1∘1^\circ the relations ti>0t_i > 0 (1≤i≤n1 \leq i \leq n) imply φ(t1,t2,…,tn)>0\varphi(t_1, t_2, \ldots, t_n) > 0; 2∘2^\circ the function φ\varphi is positively homogeneous; 3∘3^\circ the set K⊂RnK \subset \mathbf{R}^n defined by the relations ti≥0t_i \geq 0 (1≤i≤n1 \leq i \leq n), φ(t1,t2,…,tn)≥1\varphi(t_1, t_2, \ldots, t_n) \geq 1 is convex. Under these conditions, if f1,f2,…,fnf_1, f_2, \ldots, f_n are nn finite functions ≥0\geq 0 defined on XX, such that M(fi)<+∞M(f_i) < +\infty for 1≤i≤n1 \leq i \leq n, then

M(φ(f1,f2,…,fn))≤φ(M(f1),M(f2),…,M(fn)). M(\varphi(f_1, f_2, \ldots, f_n)) \leq \varphi(M(f_1), M(f_2), \ldots, M(f_n)).

One knows, by the Hahn-Banach theorem (TVS, II, §5), that KK is the intersection of the nn half-spaces ti≥0t_i \geq 0 (1≤i≤n1 \leq i \leq n) and a family of closed half-spaces (Uι)ι∈I(U_\iota)_{\iota \in I}, UιU_\iota being defined by a relation of the form

αι1t1+αι2t2+⋯+αιntn−βι≥0, \alpha_{\iota 1} t_1 + \alpha_{\iota 2} t_2 + \cdots + \alpha_{\iota n} t_n - \beta_\iota \geq 0,

where the αιk\alpha_{\iota k} are not all zero. By hypothesis, if t=(ti)t = (t_i) is such that ti>0t_i > 0 for 1≤i≤n1 \leq i \leq n, then φ(t1,…,tn)>0\varphi(t_1, \ldots, t_n) > 0, therefore there exists a λ0>0\lambda_0 > 0 such that the relation λ≥λ0\lambda \geq \lambda_0 implies λt∈K\lambda t \in K; this shows that, for each ι∈I\iota \in I, the relations ti≥0t_i \geq 0 (1≤i≤n1 \leq i \leq n) imply αι1t1+⋯+αιntn≥0\alpha_{\iota 1} t_1 + \cdots + \alpha_{\iota n} t_n \geq 0 and therefore αιk≥0\alpha_{\iota k} \geq 0 for 1≤k≤n1 \leq k \leq n; it is then clear that KK is also the intersection of the half-spaces ti≥0t_i \geq 0 (1≤i≤n1 \leq i \leq n) and the UιU_\iota such that βι≥0\beta_\iota \geq 0; moreover, since the origin does not belong to KK, there exists at least one index ι\iota such that βι>0\beta_\iota > 0.

Now let CC be the convex cone in Rn+1\mathbf{R}^{n+1} defined by the relations ti≥0t_i \geq 0 (1≤i≤n+11 \leq i \leq n+1), tn+1≤φ(t1,t2,…,tn)t_{n+1} \leq \varphi(t_1, t_2, \ldots, t_n) (the closure of the convex cone generated in Rn+1\mathbf{R}^{n+1} by the convex set K×{1}K \times \{1\}); it is immediate that CC is also defined by the relations ti≥0t_i \geq 0 (1≤i≤n+11 \leq i \leq n+1) and

βιtn+1≤αι1t1+⋯+αιntn(ι∈I, βι≥0). \beta_\iota t_{n+1} \leq \alpha_{\iota 1} t_1 + \cdots + \alpha_{\iota n} t_n \quad (\iota \in I, \ \beta_\iota \geq 0).

For every x∈Xx \in X, we therefore have

βιφ(f1(x),…,fn(x))≤αι1f1(x)+⋯+αιnfn(x) \beta_\iota \varphi(f_1(x), \ldots, f_n(x)) \leq \alpha_{\iota 1} f_1(x) + \cdots + \alpha_{\iota n} f_n(x)

for all ι∈I\iota \in I. For every index ι\iota such that βι>0\beta_\iota > 0, it follows from (4) and the hypotheses on MM that M(φ(f1,f2,…,fn))M(\varphi(f_1, f_2, \ldots, f_n)) is finite and

βιM(φ(f1,f2,…,fn))≤αι1M(f1)+αι2M(f2)+⋯+αιnM(fn), \beta_\iota M(\varphi(f_1, f_2, \ldots, f_n)) \leq \alpha_{\iota 1} M(f_1) + \alpha_{\iota 2} M(f_2) + \cdots + \alpha_{\iota n} M(f_n),

and this relation is also verified in an obvious manner if βι=0\beta_\iota = 0. We thus see that the point with coordinates

M(f1),M(f2),…,M(fn),M(φ(f1,f2,…,fn)) M(f_1), M(f_2), \ldots, M(f_n), \quad M(\varphi(f_1, f_2, \ldots, f_n))

belongs to CC, which proves the proposition.

2. The inequalities of Hölder and Minkowski

In this No. and in the following one, XX and PP have the same meaning as in No. 1, and MM denotes a function defined on PP that satisfies the conditions listed in No. 1.

PROPOSITION 2. — Let α\alpha and β\beta be two numbers such that 0<α<10 < \alpha < 1, 0<β<10 < \beta < 1, α+β=1\alpha + \beta = 1. If ff and gg are two finite functions ≥0\geq 0 defined on XX, and if M(f)M(f) and M(g)M(g) are finite, then

M(fαgβ)≤(M(f))α(M(g))β M(f^\alpha g^\beta) \leq (M(f))^\alpha (M(g))^\beta

(Hölder’s inequality).

By Prop. 1, it all comes down to proving that, in R2\mathbf{R}^2, the set defined by the relations t1≥0t_1 \geq 0, t2≥0t_2 \geq 0, t1αt2β≥1t_1^\alpha t_2^\beta \geq 1 is convex, or again (FRV, I, §4, No. 1, Def. 1) that the function u(t)=t−α/βu(t) = t^{-\alpha/\beta} is convex for 0<t<+∞0 < t < +\infty. Now, setting r=α/βr = \alpha/\beta, we have D2u(t)=r(r+1)t−r−2D^2 u(t) = r(r+1)t^{-r-2} and, since r>0r > 0, D2u(t)>0D^2 u(t) > 0 on ]0,+∞[]0, +\infty[, which proves the proposition (FRV, I, §4, No. 4, Cor. of Prop. 8).

COROLLARY. — Let αi\alpha_i (1≤i≤n1 \leq i \leq n) be nn numbers ≥0\geq 0 such that

∑i=1nαi=1, \sum_{i=1}^n \alpha_i = 1,
and let fif_i (1≤i≤n1 \leq i \leq n) be nn functions ≥0\geq 0 defined on XX, such that M(fi)M(f_i) is finite for 1≤i≤n1 \leq i \leq n. Under these conditions,

M(f1α1f2α2⋯fnαn)≤(M(f1))α1(M(f2))α2⋯(M(fn))αn. M(f_1^{\alpha_1} f_2^{\alpha_2} \cdots f_n^{\alpha_n}) \leq (M(f_1))^{\alpha_1} (M(f_2))^{\alpha_2} \cdots (M(f_n))^{\alpha_n}.

We can restrict attention to the case that αi>0\alpha_i > 0 for every ii. It suffices to argue by induction on nn, by applying the inequality (5) to the numbers α=α1\alpha = \alpha_1 and β=∑i=2nαi\beta = \sum_{i=2}^n \alpha_i, and to the functions f=f1f = f_1, g=(f2α2f3α3⋯fnαn)1/βg = (f_2^{\alpha_2} f_3^{\alpha_3} \cdots f_n^{\alpha_n})^{1/\beta}.

PROPOSITION 3. — Let pp be a real number ≥1\geq 1. If ff and gg are two finite functions ≥0\geq 0 defined on XX, then

(M((f+g)p))1/p≤(M(fp))1/p+(M(gp))1/p \left( M((f+g)^p) \right)^{1/p} \leq \left( M(f^p) \right)^{1/p} + \left( M(g^p) \right)^{1/p}

(Minkowski’s inequality).

We can restrict attention to the case that M(fp)M(f^p) and M(gp)M(g^p) are finite. By Prop. 1, we are reduced to proving that the set in R2\mathbf{R}^2 defined by the relations t1≥0, t2≥0, t11/p+t21/p≥1t_1 \geq 0,\ t_2 \geq 0,\ t_1^{1/p} + t_2^{1/p} \geq 1 is convex, or again that the function u(t)=(1−t1/p)pu(t) = (1 - t^{1/p})^p is convex for 0≤t≤10 \leq t \leq 1. Now,

D2u(t)=(1−1p)t1/p−2(1−t1/p)p−2≥0 D^2 u(t) = \left(1 - \frac{1}{p}\right)t^{1/p-2}(1-t^{1/p})^{p-2} \geq 0

for 0<t≤10 < t \leq 1, whence the proposition.

3. The semi-norms NpN_p

Let pp be a real number ≥1\geq 1 and let Fp(X,M)\mathscr{F}^p(X, M) be the set of finite numerical functions ff defined on XX such that M(∣f∣p)M(|f|^p) is finite. It is obvious that if gg is a function belonging to Fp(X,M)\mathscr{F}^p(X, M) and if ∣f∣≤∣g∣|f| \leq |g|, then ff also belongs to Fp(X,M)\mathscr{F}^p(X, M); this remark and Minkowski’s inequality show that the sum of two functions in Fp(X,M)\mathscr{F}^p(X, M) also belongs to this set; taking into account the fact that MM is positively homogeneous, we thus see that Fp(X,M)\mathscr{F}^p(X, M) is a linear subspace of the space RX\mathbf{R}^X of all finite numerical functions defined on XX.

For every number p>0p > 0 and every finite numerical function ff defined on XX, set

Np(f)=(M(∣f∣p))1/p; N_p(f) = \left(M(|f|^p)\right)^{1/p};

then Np(λf)=∣λ∣Np(f)N_p(\lambda f) = |\lambda| N_p(f) for every scalar λ\lambda; moreover, if p≥1p \geq 1 then, by (7),

Np(f+g)≤Np(f)+Np(g), N_p(f+g) \leq N_p(f) + N_p(g),

which proves that NpN_p is a semi-norm on the vector space Fp(X,M)\mathscr{F}^p(X, M) (TVS, II, §1).

Proposition 4. — Let pp and qq be two real numbers >0> 0 and set 1/r=1/p+1/q1/r = 1/p + 1/q. For any finite numerical functions f,gf, g defined on XX,

Nr(fg)≤Np(f)Nq(g) N_r(fg) \leq N_p(f) N_q(g)

provided that Np(f)N_p(f) and Nq(g)N_q(g) are finite.

For, the relation (9) may be written

M(∣f∣r∣g∣r)≤(M(∣f∣p))r/p(M(∣g∣q))r/q, M(|f|^r |g|^r) \leq (M(|f|^p))^{r/p} (M(|g|^q))^{r/q},

which is none other than Hölder’s inequality (5) applied to the numbers α=r/p\alpha = r/p and β=r/q\beta = r/q and to the functions ∣f∣p|f|^p and ∣g∣q|g|^q.

COROLLARY. — Suppose that M(1)=1M(1) = 1; then, for every finite numerical function ff defined on XX, the mapping p↦Np(f)p \mapsto N_p(f) is increasing in ]0,+∞[]0, +\infty[.

Applying the inequality (9) to the case that g=1g = 1, we see that Nr(f)≤Np(f)N_r(f) \leq N_p(f) for all q>0q > 0; since the number rr defined by 1/r=1/p+1/q1/r = 1/p + 1/q runs over the set of numbers such that 0<r<p0 < r < p when qq runs over the set of numbers >0> 0, the corollary is proved.

PROPOSITION 5. — For every finite numerical function ff defined on XX, the set II of values of 1/p1/p (p>0p > 0) such that Np(f)N_p(f) is finite is either empty or is an interval; if II is not reduced to a point, then the mapping α↦log⁡N1/α(f)\alpha \mapsto \log N_{1/\alpha}(f) is either convex on II or is equal to −∞-\infty on the interior of II.

Let rr and ss be two distinct numbers >0> 0 such that 1/r1/r and 1/s1/s belong to II; it all comes down to proving that if

1p=tr+1−ts, \frac{1}{p} = \frac{t}{r} + \frac{1-t}{s},

with 0<t<10 < t < 1, then

log⁡Np(f)≤t⋅log⁡Nr(f)+(1−t)log⁡Ns(f), \log N_p(f) \leq t \cdot \log N_r(f) + (1-t) \log N_s(f),

or, what comes to the same,

Np(f)≤(Nr(f))t(Ns(f))1−t, N_p(f) \leq (N_r(f))^t (N_s(f))^{1-t},

a relation that may, by the definition of NpN_p, be written

M(∣f∣p)≤(M(∣f∣r))tp/r(M(∣f∣s))(1−t)p/s. M(|f|^p) \leq (M(|f|^r))^{tp/r} (M(|f|^s))^{(1-t)p/s}.

Setting α=tp/r\alpha = tp/r, we have 1−α=(1−t)p/s1-\alpha = (1-t)p/s by the relation that defines pp as a function of t,r,st, r, s; whence p=αr+(1−α)sp = \alpha r + (1-\alpha)s. Hölder’s inequality now yields

M(∣f∣rα∣f∣s(1−α))≤(M(∣f∣r))α(M(∣f∣s))1−α, M(|f|^{r\alpha}|f|^{s(1-\alpha)}) \leq (M(|f|^r))^{\alpha} (M(|f|^s))^{1-\alpha},

which is none other than the inequality (12).

Exercises

1) With the hypotheses of No. 1, show that the set of bounded functions on X such that M(∣f∣)M(|f|) is finite is a subalgebra A of RX\mathbf{R}^X, and that the set of bounded functions on X such that M(∣f∣)=0M(|f|) = 0 is an ideal in A. If, moreover, M(1)M(1) is finite, show that the mapping f↦M(f)f \mapsto M(f) is continuous when A is equipped with the topology of uniform convergence in X.

2) Let X be the interval [0,+∞[[0, +\infty[ of R\mathbf{R}, S the convex cone formed by the functions defined on X such that 0≤f(x)≤kx0 \leq f(x) \leq kx on X (for a finite number k>0k > 0 depending on ff). Set M(f)=0M(f) = 0 for f∈Sf \in S, and M(f)=+∞M(f) = +\infty for every positive function ff defined on X and not belonging to S. Show that MM satisfies the conditions of No. 1, and that M(x)=0M(x) = 0, and M(xr)=+∞M(x^r) = +\infty for every number r>0r > 0 not equal to 1.

3) Give an example where X is a set with two elements, Np(x)N_p(\mathbf{x}) is finite for every p>0p > 0 and every x∈R2\mathbf{x} \in \mathbf{R}^2, but where there exist values of pp such that the mapping p↦Np(x)p \mapsto N_p(\mathbf{x}) is not differentiable at these points.

4) Deduce the inequality (6) from the inequality of the geometric mean

z1α1z2α2⋯znαn≤α1z1+⋯+αnzn(where ∑i=1nαi=1) z_1^{\alpha_1} z_2^{\alpha_2} \cdots z_n^{\alpha_n} \leq \alpha_1 z_1 + \cdots + \alpha_n z_n \quad \text{(where } \sum_{i=1}^n \alpha_i = 1 \text{)}

(FRV, III, §1, No. 1, Prop. 2). (Reduce to the case that M(fi)=1M(f_i) = 1 for 1≤i≤n1 \leq i \leq n.)

5) Let α\alpha be a real number >1> 1 and let β=1−α<0\beta = 1 - \alpha < 0. Let gg be a finite function, defined on X, such that g(x)>0g(x) > 0 for all x∈Xx \in X and such that M(g)>0M(g) > 0; show that for every finite function f≥0f \geq 0 defined on X such that M(f)M(f) is finite,

M(fαgβ)≥(M(f))α(M(g))β M(f^\alpha g^\beta) \geq (M(f))^\alpha (M(g))^\beta

(apply Hölder’s inequality suitably).

6) Deduce Minkowski’s inequality from Hölder’s inequality (find an upper bound for M((f+g)p−1)M((f+g)^{p-1}) with the help of Hölder’s inequality). If one assumes that M(f+g)=M(f)+M(g)M(f+g) = M(f) + M(g) for every pair of functions f,gf, g defined and ≥0\geq 0 on XX, deduce similarly from Exer. 5 the inequality

(M((f+g)p))1/p≥(M(fp))1/p+(M(gp))1/p (M((f+g)^p))^{1/p} \geq (M(f^p))^{1/p} + (M(g^p))^{1/p}

in the following cases:

a) 0<p<10 < p < 1, ff and gg finite functions ≥0\geq 0 defined on XX, such that f(x)+g(x)>0f(x) + g(x) > 0 for all x∈Xx \in X and such that M(fp)M(f^p) and M(gp)M(g^p) are finite;

b) p<0p < 0, ff and gg finite functions defined on XX, such that f(x)>0f(x) > 0 and g(x)>0g(x) > 0 for all x∈Xx \in X, M(fp)M(f^p) and M(gp)M(g^p) are finite, and M((f+g)p)>0M((f+g)^p) > 0.

Transcribed from the printed volume. Not translated.