Bourbaki

Exercise 3, § 1

Integration, II

a) Let E be a Riesz space, H a linear subspace of E. If, for any pair of elements x,yx, y of H, sup⁡(x,y)\sup(x, y) belongs to H, then H is said to be a co-lattice subspace. For this to be the case, it is necessary and sufficient that the relation x∈Hx \in H imply ∣x∣∈H|x| \in H.

b) Let I be a compact interval in R\mathbf{R}, H the subspace of RI\mathbf{R}^I formed by the restrictions to I of the first-degree polynomials t↦αt+βt \mapsto \alpha t + \beta. Show that H is not a co-lattice subspace of RI\mathbf{R}^I but that H is a Riesz space (for the structure induced by that of RI\mathbf{R}^I).

Solution

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Transcribed from the printed volume. Not translated.