Bourbaki

Exercise 7, § 1

Integration, II, p. 16

Let E be a fully lattice-ordered space, H an isolated subspace of E (Exer. 4). If B1B_1 and B2B_2 are two supplementary bands in E, show that H is the ordered direct sum of H1=H∩B1H_1 = H \cap B_1 and H2=H∩B2H_2 = H \cap B_2, and that the Riesz space E/HE/H is the ordered direct sum of the Riesz spaces B1/H1B_1/H_1 and B2/H2B_2/H_2.

Solution

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Transcribed from the printed volume. Not translated.