Bourbaki

Exercise 6, § 4

Integration, III, p. 61

Bourbaki marks this one as harder than the rest.

With the notations of No. 6 show that, for there to exist a measure μ≠0\mu \neq 0 on XX such that

μ(fJ∘prJ)=lim⁡K⊃JμK(fJ∘prJ,K)=μJ(fJ)⋅∏λ∈L−Jμλ(1) \mu(f_J \circ \mathrm{pr}_J) = \lim_{K \supset J} \mu_K(f_J \circ \mathrm{pr}_{J, K}) = \mu_J(f_J) \cdot \prod_{\lambda \in L - J} \mu_\lambda(1)

for every finite subset JJ of LL and every function fJ∈C(XJ;C)f_J \in \mathscr{C}(X_J; \mathbf{C}), it is necessary and sufficient that the following three conditions be satisfied:

1∘1^\circ μλ≠0\mu_\lambda \neq 0 for all λ∈L\lambda \in L. 2∘2^\circ There exists a finite subset J0J_0 of LL such that the family (μλ(1))λ∈L−J0(\mu_\lambda(1))_{\lambda \in L - J_0} is multipliable in C∗\mathbf{C}^* (hence has a product ≠0\neq 0). 3∘3^\circ The family (∥μλ∥)λ∈L(\|\mu_\lambda\|)_{\lambda \in L} is multipliable in R+∗\mathbf{R}_+^* (hence has a product ≠0\neq 0).

Under what conditions is the second member of (1) equal to 0 for every finite subset JJ of LL and every function fJ∈C(XJ;C)f_J \in \mathscr{C}(X_J; \mathbf{C})?

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.