Bourbaki

Exercise 1, § 5

Integration, IV, p. 127

Bourbaki marks this one as harder than the rest.

Let I be a semi-open interval ]a,b]]a, b] in R\mathbf{R}, and let F=RIF = \mathbf{R}^I be the space of all mappings of I into R\mathbf{R}, equipped with the topology of pointwise convergence; for every x∈Ix \in I, denote by f(x)f(x) the mapping t↦∣x−t∣t \mapsto |x - t| of I into R\mathbf{R}, which is an element of F; the mapping f of I into F is continuous. Show that f is left-differentiable at every point of I, but the left-derivative fl′f'_l is a function (with values in F) that is not measurable for Lebesgue measure, even though it is the pointwise limit of a sequence of continuous functions and, for each t∈It \in I, the function pr⁡t∘fl′\operatorname{pr}_t \circ f'_l is a measurable numerical function (note that fl′f'_l is not right-continuous at any point of I, and make use of Exer. 1 of GT, IV, §2).

Solution

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Transcribed from the printed volume. Not translated.