Bourbaki

Exercise 12, § 5

Integration, IV, p. 128

Bourbaki marks this one as harder than the rest.

Let μ\mu be a measure ⩾0\geqslant 0 on XX. Let (fn)(f_n) be a sequence of integrable functions on XX that converges pointwise on XX to a function ff.

a) Show that if ff is integrable and if

∫f dμ=lim⁡n→∞∫fn dμ, \int f \, d\mu = \lim_{n \to \infty} \int f_n \, d\mu,

then for every ε>0\varepsilon > 0 there exist an integrable set AA, an integrable function g⩾0g \geqslant 0, and an integer n0n_0 such that, for every n⩾n0n \geqslant n_0,

∣∫fnφCAdμ∣⩽ε \left| \int f_n \varphi_{\mathbf{C}_A} d\mu \right| \leqslant \varepsilon

and ∣fn(x)∣⩽g(x)|f_n(x)| \leqslant g(x) for all x∈Ax \in A (consider an integrable set BB such that

∫∣f∣φCBdμ⩽ε/2 \int |f| \varphi_{\mathbf{C}_B} d\mu \leqslant \varepsilon/2

and such that ff is bounded on BB, and apply Egoroff’s theorem).

b) Suppose that, for every ε>0\varepsilon > 0, there exist a measurable set AA, an integrable function g⩾0g \geqslant 0 and an integer n0n_0 such that, for every n⩾n0n \geqslant n_0, one has ∫∣fn∣φCAdμ⩽ε\int |f_n| \varphi_{\mathbf{C}_A} d\mu \leqslant \varepsilon and ∣fn(x)∣⩽g(x)|f_n(x)| \leqslant g(x) for all x∈Ax \in A. Show that, under these conditions, ff is integrable and fnf_n tends to ff in the space L1L^1. Converse.

c) Suppose that F=RF = \mathbf{R}; show by means of examples that the conditions of a) are not sufficient, and that the conditions of b) are not necessary, for ff to be integrable and for ∫f dμ=lim⁡n→∞∫fn dμ\int f \, d\mu = \lim_{n \to \infty} \int f_n \, d\mu to hold.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.