Integration, IV, p. 133
Bourbaki marks this one as harder than the rest.
Let Φ(t,u,v) be a finite and continuous numerical function for 0⩽t⩽1, u⩾0, v⩾0. For every numerical function f⩾0 defined on I=[0,1], measurable for Lebesgue measure, f∗ denotes the decreasing rearrangement of f (Exer. 29). In order that, for every pair of functions f⩾0, g⩾0, measurable (for Lebesgue measure) and bounded on I, one have
∫01Φ(t,f(t),g(t))dt⩽∫01Φ(t,f∗(t),g∗(t))dt,
it is necessary and sufficient that the function Φ satisfy the following three conditions:
(2)
Φ(t,u+h,v+h)−Φ(t,u+h,v)−Φ(t,u,v+h)+Φ(t,u,v)⩾0 for all
t∈I,
u⩾0,
v⩾0 and
h⩾0;
(3)
∫0δ(Φ(a+δ+t,u,v)−Φ(a+δ+t,u+h,v)+Φ(a+t,u+h,v)−Φ(a+t,u,v))dt⩾0
and
∫0δ(Φ(a+δ+t,u,v)−Φ(a+δ+t,u,v+h)+Φ(a+t,u,v+h)−Φ(a+t,u,v))dt≥0
for all a,h,δ such that 0≤a≤1−2δ, h≥0.
(To prove that (3) and (4) are necessary, take f and g to be suitable step functions; next deduce (2) from (3) and (4). To prove that the conditions are sufficient, first deduce from (2), using the continuity of Φ, that
Φ(t,u+h,v+k)−Φ(t,u+h,v)−Φ(t,u,v+k)+Φ(t,u,v)≥0
for all t∈I, u≥0, v≥0, h≥0, k≥0. Then using (3) and (4), prove (1) when f and g are step functions whose points of discontinuity in I are of the form r/n (0≤r≤n), by comparing successively the integrals
∫01Φ(t,fi(t),gi(t))dt
and
∫01Φ(t,fj(t),gj(t))dt,
where fi and gi differ from fj and gj only in two consecutive intervals [(r−1)/n,r/n] and [r/n,(r+1)/n]. Finally, pass to the limit in a suitable way to prove (1) in the general case.)
If Φ is twice continuously differentiable, the conditions (2), (3) and (4) are equivalent, respectively, to
∂u∂v∂2Φ≥0,∂t∂u∂2Φ≤0,∂t∂v∂2Φ≤0.
Generalize to functions Φ(t,u1,…,um) of any number of variables.