Bourbaki

Exercise 30, § 5

Integration, IV, p. 133

Bourbaki marks this one as harder than the rest.

Let Φ(t,u,v)\Phi(t,u,v) be a finite and continuous numerical function for 0⩽t⩽10 \leqslant t \leqslant 1, u⩾0u \geqslant 0, v⩾0v \geqslant 0. For every numerical function f⩾0f \geqslant 0 defined on I=[0,1]I = [0,1], measurable for Lebesgue measure, f∗f^* denotes the decreasing rearrangement of f (Exer. 29). In order that, for every pair of functions f⩾0f \geqslant 0, g⩾0g \geqslant 0, measurable (for Lebesgue measure) and bounded on I, one have

∫01Φ(t,f(t),g(t))dt⩽∫01Φ(t,f∗(t),g∗(t))dt, \int_0^1 \Phi(t,f(t),g(t)) dt \leqslant \int_0^1 \Phi(t,f^*(t),g^*(t)) dt,

it is necessary and sufficient that the function Φ\Phi satisfy the following three conditions:

(2)

Φ(t,u+h,v+h)−Φ(t,u+h,v)−Φ(t,u,v+h)+Φ(t,u,v)⩾0 \Phi(t,u+h,v+h) - \Phi(t,u+h,v) - \Phi(t,u,v+h) + \Phi(t,u,v) \geqslant 0
for all t∈It \in I, u⩾0u \geqslant 0, v⩾0v \geqslant 0 and h⩾0h \geqslant 0;

(3)

∫0δ(Φ(a+δ+t,u,v)−Φ(a+δ+t,u+h,v)+Φ(a+t,u+h,v)−Φ(a+t,u,v))dt⩾0 \int_0^\delta (\Phi(a+\delta+t,u,v) - \Phi(a+\delta+t,u+h,v) \\ + \Phi(a+t,u+h,v) - \Phi(a+t,u,v)) dt \geqslant 0

and

∫0δ(Φ(a+δ+t,u,v)−Φ(a+δ+t,u,v+h)+Φ(a+t,u,v+h)−Φ(a+t,u,v))dt≥0 \int_0^\delta (\Phi(a + \delta + t, u, v) - \Phi(a + \delta + t, u, v + h) + \Phi(a + t, u, v + h) - \Phi(a + t, u, v)) dt \geq 0

for all a,h,δa, h, \delta such that 0≤a≤1−2δ, h≥00 \leq a \leq 1 - 2\delta ,\ h \geq 0.

(To prove that (3) and (4) are necessary, take ff and gg to be suitable step functions; next deduce (2) from (3) and (4). To prove that the conditions are sufficient, first deduce from (2), using the continuity of Φ\Phi, that

Φ(t,u+h,v+k)−Φ(t,u+h,v)−Φ(t,u,v+k)+Φ(t,u,v)≥0 \Phi(t, u + h, v + k) - \Phi(t, u + h, v) - \Phi(t, u, v + k) + \Phi(t, u, v) \geq 0

for all t∈I, u≥0, v≥0, h≥0, k≥0t \in I,\ u \geq 0,\ v \geq 0,\ h \geq 0,\ k \geq 0. Then using (3) and (4), prove (1) when ff and gg are step functions whose points of discontinuity in II are of the form r/nr/n (0≤r≤n0 \leq r \leq n), by comparing successively the integrals

∫01Φ(t,fi(t),gi(t))dt \int_0^1 \Phi(t, f_i(t), g_i(t)) dt

and

∫01Φ(t,fj(t),gj(t))dt, \int_0^1 \Phi(t, f_j(t), g_j(t)) dt ,

where fif_i and gig_i differ from fjf_j and gjg_j only in two consecutive intervals [(r−1)/n,r/n][ (r-1)/n, r/n ] and [r/n,(r+1)/n][ r/n, (r+1)/n ]. Finally, pass to the limit in a suitable way to prove (1) in the general case.)

If Φ\Phi is twice continuously differentiable, the conditions (2), (3) and (4) are equivalent, respectively, to

∂2Φ∂u∂v≥0,∂2Φ∂t∂u≤0,∂2Φ∂t∂v≤0. \frac{\partial^2 \Phi}{\partial u \partial v} \geq 0 ,\quad \frac{\partial^2 \Phi}{\partial t \partial u} \leq 0 ,\quad \frac{\partial^2 \Phi}{\partial t \partial v} \leq 0 .

Generalize to functions Φ(t,u1,…,um)\Phi(t, u_1, \ldots, u_m) of any number of variables.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.