Exercise 15, § 6
Integration, IV, p. 138
Bourbaki marks this one as harder than the rest.
Let X be a compact space, a positive measure on X. For two functions of , one sets . A sequence of functions is said to be orthonormal if the sequence is orthonormal in the Hilbert space , that is (TVS, V, §2) if (the Kronecker symbol) for every pair of indices. For every function , the complex numbers are called the components of with respect to the orthonormal sequence ; one has .
For every pair of points of X and every integer , one sets (the n-th kernel of the orthonormal sequence ); for every function ,
Set (called the n-th Lebesgue function of the orthonormal sequence ).
a) Let be a decreasing sequence of numbers such that the series with general term is convergent. Show that, for almost every , (using Prop. 6 of §3, show that the series with general term is convergent almost everywhere, and make use of Exer. 10 of GT, IV, §7). Deduce from this that for almost every .
b) Let be a point of X. In order that, for every complex-valued function , defined and continuous on X, the partial sums be bounded at the point (by a number depending on and ), it is necessary and sufficient that the set of numbers be bounded (make use of Prop. 3 and the fact that in the dual of a Banach space, every weakly bounded set is strongly bounded).
c) In order that, for every complex-valued function , defined and continuous on X, the series with general term be uniformly convergent in X and have sum , it is necessary and sufficient that: 1° every continuous complex-valued function on X be uniformly approximable by linear combinations of the ; 2° there exist a constant such that for all and . (Note that for every , identically; on the other hand, to prove the necessity of the condition , note that for every increasing sequence of integers and every sequence of points of , the sequence of numbers is bounded (by a number depending on ) and argue as in .)
Solution
No solution has been written yet.