Bourbaki

Exercise 17, § 6

Integration, IV, p. 139

Bourbaki marks this one as harder than the rest.

Let μ\mu be Lebesgue measure on X=[0,1]X = [0, 1]. One defines the sequence (fn)(f_n) of step functions on XX by the following conditions: f0f_0 is the constant 1; for every integer n>0n > 0, let mm be the largest integer such that 2m≤n2^m \leq n, and write n=2m+kn = 2^m + k; fnf_n is the function equal to 2m/22^{m/2} on the interval [2k2m+1,2k+12m+1][\frac{2k}{2^{m+1}}, \frac{2k+1}{2^{m+1}}], to −2m/2-2^{m/2} on the interval [2k+12m+1,2k+22m+1][\frac{2k+1}{2^{m+1}}, \frac{2k+2}{2^{m+1}}], and to 0 at the other points of XX.

a) Show that the sequence (fn)(f_n) is orthonormal (the Haar orthonormal system).

b) Let VnV_n be the linear subspace of LC2\mathscr{L}_C^2 (over C\mathbf{C}) generated by the fkf_k with indices k≤nk \leq n. Show that there exists a partition of [0,1[[0, 1[ into n+1n+1 semi-open intervals such that, in each of these intervals, every function belonging to VnV_n is constant. Deduce from this that, conversely, for every function gg that is constant on each of these n+1n+1 intervals, there exists a function in VnV_n that is equal to gg on [0,1[[0, 1[ (note that VnV_n has dimension n+1n+1).

c) Let gg be any function in LC2\mathscr{L}_C^2; deduce from b) that if hh is the unique function in VnV_n for which N2(g−h)N_2(g-h) is minimal, then, in every interval [α,β[[\alpha, \beta[ where hh is constant, one has h(x)=1β−α∫αβg(t) dth(x) = \frac{1}{\beta-\alpha} \int_\alpha^\beta g(t)\, dt.

d) Show that for every complex-valued function gg, defined and continuous on XX, the series with general term (g∣fn)fn(x)(g|f_n)f_n(x) is uniformly convergent on [0,1[[0, 1[ and has sum g(x)g(x) (make use of c)). Deduce from this that the sequence (fn)(f_n) is total.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.