Bourbaki

Exercise 6, § 7

Integration, IV, p. 145

Bourbaki marks this one as harder than the rest.

Let XX be a nonempty compact space, H\mathscr{H} a linear subspace of C(X;R)\mathscr{C}(X; \mathbf{R}) containing the constants and separating the points of XX. The relation λ≺μ\lambda \prec \mu defined by H\mathscr{H} (Exer. 2) is then an equivalence relation, and the points H\mathscr{H}-extremal in the sense of Exer. 3 are identical to the points H\mathscr{H}-extremal in the sense of No. 3. Let FF be a closed subset of XX containing ChH(X)\mathrm{Ch}_{\mathscr{H}}(X); for every x∈Xx \in X, denote by MxF\mathscr{M}_x^F the set of positive measures μ\mu on XX, of total mass 1, such that εx≺μ\varepsilon_x \prec \mu and Supp(μ)⊂F\mathrm{Supp}(\mu) \subset F; in order that εx∈MxF\varepsilon_x \in \mathscr{M}_x^F, it is necessary and sufficient that x∈Fx \in F; the relation x∈ChH(X)x \in \mathrm{Ch}_{\mathscr{H}}(X) is equivalent to MxF={εx}\mathscr{M}_x^F = \{\varepsilon_x\}. For every bounded numerical function ff defined on FF and for every x∈Xx \in X, set

H‾xF(f)=inf⁡f≤h∣F, h∈Hh(x),H‾xF(f)=−H‾xF(−f)=sup⁡f≥h∣F, h∈Hh(x), \overline{H}_x^F(f) = \inf_{f \leq h|F,\ h \in \mathscr{H}} h(x), \quad \underline{H}_x^F(f) = -\overline{H}_x^F(-f) = \sup_{f \geq h|F,\ h \in \mathscr{H}} h(x),
which are finite numbers.

a) Show that the mapping f↦H‾xF(f)f \mapsto \overline{H}_x^F(f) of C(F;R)\mathscr{C}(F; \mathbf{R}) into R\mathbf{R} is increasing, positively homogeneous and convex. If h∈Hh \in \mathscr{H}, then H‾xF(h)=h(x)\overline{H}_x^F(h) = h(x).

b) For every x∈Xx \in X, every measure μ∈MxF\mu \in \mathscr{M}_x^F and every function f∈C(F;R)f \in \mathscr{C}(F; \mathbf{R}), H‾xF(f)≤∫fdμ≤H‾xF(f)\underline{H}_x^F(f) \leq \int f d\mu \leq \overline{H}_x^F(f). Conversely if, for a function f0∈C(F;R)f_0 \in \mathscr{C}(F; \mathbf{R}), γ\gamma is a real number such that H‾xF(f0)≤γ≤H‾xF(f0)\underline{H}_x^F(f_0) \leq \gamma \leq \overline{H}_x^F(f_0), then there exists a measure μ∈MxF\mu \in \mathscr{M}_x^F such that γ=∫f0dμ\gamma = \int f_0 d\mu.

c) Show that for a function g∈C(X;R)g \in \mathscr{C}(X; \mathbf{R}), the following conditions are equivalent: α\alpha For every x∈Xx \in X and every measure μ∈MxF\mu \in \mathscr{M}_x^F, one has g(x)=∫gdμg(x) = \int g d\mu. β\beta For every x∈Xx \in X, H‾xF(g∣F)=H‾xF(g∣F)=g(x)\underline{H}_x^F(g|F) = \overline{H}_x^F(g|F) = g(x). γ\gamma For every ε>0\varepsilon > 0 there exist two finite sequences (hi′),(hj′′)(h_i'), (h_j'') of functions in H\mathscr{H} such that, setting h′=sup⁡(hi′)h' = \sup(h_i'), h′′=inf⁡(hj′′)h'' = \inf(h_j''), one has h′≤g≤h′′h' \leq g \leq h'' and h′′−h′≤εh'' - h' \leq \varepsilon. (To see that β\beta implies γ\gamma), argue as in GT, X, §4, No. 1, Prop. 2.)

When a function g∈C(X;R)g \in \mathscr{C}(X; \mathbf{R}) has the preceding equivalent properties, it is said to be H\mathscr{H}-harmonic; the set Hc\mathscr{H}^c of H\mathscr{H}-harmonic functions is a closed linear subspace of C(X;R)\mathscr{C}(X; \mathbf{R}) containing H\mathscr{H}; it is independent of the closed set F⊃ChH(X)F \supset \mathrm{Ch}_{\mathscr{H}}(X) under consideration. One has (Hc)c=Hc(\mathscr{H}^c)^c = \mathscr{H}^c, and the equivalence relation in M+(X)\mathscr{M}_+(X) defined by Hc\mathscr{H}^c is identical to the relation λ≺μ\lambda \prec \mu defined by H\mathscr{H}; consequently ChHc(X)=ChH(X)\mathrm{Ch}_{\mathscr{H}^c}(X) = \mathrm{Ch}_{\mathscr{H}}(X). The mapping g↦g∣Fg \mapsto g|F is a strictly increasing isometry of Hc\mathscr{H}^c onto its image in C(F;R)\mathscr{C}(F; \mathbf{R}) (which is therefore a closed subspace of C(F;R)\mathscr{C}(F; \mathbf{R})).

d) Take for XX the interval [0,1][0,1] of R\mathbf{R}, and for H\mathscr{H} the vector space of restrictions to XX of the polynomials of second degree over R\mathbf{R}. Show that Hc\mathscr{H}^c is distinct from the closure H‾\overline{\mathscr{H}} of H\mathscr{H} in C(X;R)\mathscr{C}(X; \mathbf{R}).

e) Show that in order that ChH(X)=X\mathrm{Ch}_{\mathscr{H}}(X) = X, it is necessary and sufficient that Hc=C(X;R)\mathscr{H}^c = \mathscr{C}(X; \mathbf{R}) (to prove that the condition is necessary, use bb).

f) Show that if H\mathscr{H} is lattice-ordered (in other words, is a Riesz space), then Hc=H‾\mathscr{H}^c = \overline{\mathscr{H}}. Give an example where H\mathscr{H} is not lattice-ordered and Hc=H‾\mathscr{H}^c = \overline{\mathscr{H}}.

g) Let EH\mathscr{E}_{\mathscr{H}} be the smallest closed subset of C(X;R)\mathscr{C}(X; \mathbf{R}) containing H\mathscr{H} such that the lower envelope inf⁡(u,v)\inf(u, v) of any two functions of EH\mathscr{E}_{\mathscr{H}} belongs to EH\mathscr{E}_{\mathscr{H}}. Show that the following properties are equivalent: α\alpha f∈EHf \in \mathscr{E}_{\mathscr{H}}; β\beta for every x∈Xx \in X and every measure μ∈MxX\mu \in \mathscr{M}_x^X, ∫fdμ≤f(x)\int f d\mu \leq f(x); γ\gamma H‾xX(f)=f(x)\overline{H}_x^X(f) = f(x) for every x∈Xx \in X; δ\delta for every ε>0\varepsilon > 0, there exists a finite sequence (hi)(h_i) of functions in H\mathscr{H} such that f≤inf⁡(hi)≤f+εf \leq \inf(h_i) \leq f + \varepsilon. (To see that β\beta implies γ\gamma), make use of bb.) Deduce from this that EH\mathscr{E}_{\mathscr{H}} is a pointed convex cone, and that EH∩(−EH)=Hc\mathscr{E}_{\mathscr{H}} \cap (-\mathscr{E}_{\mathscr{H}}) = \mathscr{H}^c. Show that every function in EH\mathscr{E}_{\mathscr{H}} attains its infimum in XX at at least one point of ChH(X)\mathrm{Ch}_{\mathscr{H}}(X).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.