Bourbaki

Exercise 1, § 3

Integration, IX, p. 108

Let E be a set, Φ\Phi a clan of subsets of E, and m an additive set function defined on Φ\Phi. Denote by E(Φ)\mathscr{E}(\Phi) the vector space of real Φ\Phi-step functions on E, and by J the linear form on E(Φ)\mathscr{E}(\Phi) such that J(φA)=m(A)J(\varphi_A) = m(A) for all A∈ΦA \in \Phi.

a) For every A∈ΦA \in \Phi, one sets

m+(A)=sup⁡B∈Φ,B⊂Am(B)andm−(A)=sup⁡B∈Φ,B⊂A(−m(B)). m_+(A) = \sup_{B \in \Phi, B \subset A} m(B) \quad \text{and} \quad m_-(A) = \sup_{B \in \Phi, B \subset A} (-m(B)).

Show that ∣m∣(A)=m+(A)+m−(A)|m|(A) = m_+(A) + m_-(A) is the supremum of the set of numbers of the form ∑i=1p∣m(Ai)∣\sum_{i=1}^p |m(A_i)| for all the finite partitions (Ai)1≤i≤p(A_i)_{1 \leq i \leq p} of A into sets belonging to Φ\Phi.

b) One says that m is relatively bounded if the set of numbers of the form m(B)m(B) with B∈Φ,B⊂AB \in \Phi, B \subset A is bounded for any set A∈ΦA \in \Phi. Show that the following conditions are equivalent: α)\alpha) m is relatively bounded; β)\beta) the linear form J on the Riesz space E(Φ)\mathscr{E}(\Phi) is relatively bounded; γ)\gamma) m is the difference of two positive additive set functions on Φ\Phi; δ)\delta) ∣m∣(A)|m|(A) is finite for all A∈ΦA \in \Phi (argue in a circle α\alpha) ⇒β)⇒γ)⇒δ)⇒α)\Rightarrow \beta) \Rightarrow \gamma) \Rightarrow \delta) \Rightarrow \alpha).

c) Suppose that m is relatively bounded. Show that the set functions ∣m∣,m+|m|, m_+ and m−m_- are additive and that m=m+−m−m = m_+ - m_- (make use of Th. 1 of Ch. II, §2, No. 2). Moreover, if m′m' and m′′m'' are additive and positive set functions on Φ\Phi such that m=m′−m′′m = m' - m'', then m′≥m+m' \geq m_+ and m′′≥m−m'' \geq m_-.

d) One says that m is countably additive if m(A)=∑n≥1m(An)m(A) = \sum_{n \geq 1} m(A_n) for every countable partition (An)n≥1(A_n)_{n \geq 1} of a set A∈ΦA \in \Phi into sets belonging to Φ\Phi. Show that this condition signifies that lim⁡n→∞m(An)=0\lim_{n \to \infty} m(A_n) = 0 for every decreasing sequence (An)n≥1(A_n)_{n \geq 1} of elements of Φ\Phi such that ⋂n≥1An=∅\bigcap_{n \geq 1} A_n = \emptyset. If m is countably additive, show that ∣m∣|m| is countably additive.

Solution

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Transcribed from the printed volume. Not translated.