Bourbaki

Exercise 2, § 5

Integration, IX, p. 113

Bourbaki marks this one as harder than the rest.

Let TT be a completely regular space and F\mathfrak{F} a filter on M+b(T)\mathscr{M}_+^b(T) that converges tightly to a bounded measure μ\mu. A Borel subset AA of TT is said to be a convergence set (for F\mathfrak{F}) if lim⁡λ,FλA=μA\lim_{\lambda, \mathfrak{F}} \lambda_A = \mu_A.

a) If the disjoint sets A1A_1 and A2A_2 are convergence sets, then so is A1∪A2A_1 \cup A_2.

b) Let AA be an open or closed set. For AA to be a convergence set, it is necessary and sufficient that lim⁡λ,Fλ∗(A)=μ∗(A)\lim_{\lambda, \mathfrak{F}} \lambda^*(A) = \mu^*(A). If AA is a convergence set, then so is T−AT - A.

c) Let AA be an open or closed convergence set in TT, and BB a convergence set such that T−BT - B is also a convergence set. Then A∪BA \cup B and A∩BA \cap B are convergence sets, as are their complements.

d) The clan generated by the open convergence sets consists of convergence sets.

e) Let AA be a subset of TT whose boundary is μ\mu-negligible. Then AA is a convergence set.

f) Suppose that TT is locally compact or Polish. Show that every compact subset KK of TT is contained in a compact convergence set (in case TT is locally compact, use Exercise 1 b). If TT is Polish, use the same exercise to construct a sequence of finite coverings Up\mathscr{U}_p of KK by open subsets of TT, with μ\mu-negligible boundary and of diameter <2−p< 2^{-p}; show that L=⋂p⋃U∈UpU‾L = \bigcap_p \bigcup_{U \in \mathscr{U}_p} \overline{U} is compact and conclude that it is a convergence set by b)).

g) Extend the result of f) to the case of a convergent sequence of measures on a complete metric space.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.