Bourbaki

Exercise 7, § 5

Integration, IX, p. 115

Bourbaki marks this one as harder than the rest.

Let H be a set of bounded positive measures on a topological space T. Assume that sup⁡μ∈Hμ∙(T)\sup_{\mu \in H} \mu^\bullet(T) is finite, and that for every ε>0\varepsilon > 0, there exists a compact subset K of T such that sup⁡μ∈Hμ∙(T−K)<ε\sup_{\mu \in H} \mu^\bullet(T - K) < \varepsilon. Show that the condition (V) of the preceding exercise is verified. Let U\mathscr{U} be an ultrafilter on H. The measure π\pi is defined as in the preceding exercise.

a) Show that π∙(g)≥lim⁡μ,Uμ∙(g)\pi^\bullet(g) \geq \lim_{\mu, \mathscr{U}} \mu^\bullet(g) for every upper semi-continuous bounded positive function g on T. Deduce from this that π∙(f)=lim⁡μ,Uμ∙(f)\pi^\bullet(f) = \lim_{\mu, \mathscr{U}} \mu^\bullet(f) for every bounded function f on T whose set of points of discontinuity is π\pi-negligible.

b) When T is completely regular, deduce from a) that H is relatively compact for the tight topology (this furnishes a new proof of Th. 1 of No. 5 for the case of positive measures).

Solution

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Transcribed from the printed volume. Not translated.