Integration, IX, p. 115
Bourbaki marks this one as harder than the rest.
Let T be a complete separable metric space, and d its metric. For every closed subset F of T and every real number a>0, denote by Fa the set of x∈T such that d(x,F)<a. Given two bounded positive measures λ and μ on T, denote by D(λ,μ) the infimum of the set of real numbers a>0 satisfying the inequalities λ∙(F)≤μ∙(Fa)+a, μ∙(F)≤λ∙(Fa)+a for every closed subset F of T.
a) Show that D is a metric on M+b and that D(εx,εy)=d(x,y) for two points x and y of T such that d(x,y)<1.
b) Let f be a Borel mapping of T into T (cf. TG, IX, §6, No. 3 or GT, IX, §6, Exer. 16) and λ a bounded positive measure on T. Show that there exists a bounded positive measure μ on T such that μ∙(A)=λ∙(f−1(A)) for every Borel subset A of T. Let a>0, and let H be the set of x∈T such that d(x,f(x))≥a; show that H is Borel in T and that D(λ,μ)≤sup(a,λ(H)) (for every closed subset F of T, one has F∩(T−H)⊂f−1(Fa) and λ∙(F)≤λ∙(F∩(T−H))+λ∙(H)).
c) Let μ and μn (for n≥1) be bounded positive measures on T such that limn→∞D(μn,μ)=0. Show that the sequence (μn) converges tightly to μ (show that limn→∞μn∙(T)=μ∙(T) and μ∙(F)≥limsupn→∞μn∙(F) for every closed subset F of T; deduce from this that μ∙(f)≤liminfn→∞μn∙(f) for every lower semi-continuous function f≥0 by the method of Lemma 3 of §2, No. 6).
d) Conversely, show that for every sequence of bounded positive measures μn tending tightly to μ in M+b, one has limD(μn,μ)=0. One can proceed as follows: let ε>0, and let K be a compact subset of T such that μ∙(T−K)<ε and supnμn∙(T−K)<ε; construct a finite family (Bi)1≤i≤p of sets with μ-negligible boundary, of diameter ≤ε/2, pairwise disjoint, whose union contains K (cf. Exer. 1). Let f be a mapping of T into T, constant on each of the sets B1,…,Bp and C(B1∪⋯∪Bp) and such that f(Bi)⊂Bi for 1≤i≤p. Define the measures πn and π by πn∙(A)=μn∙(f−1(A)) and π∙(A)=μ∙(f−1(A)) for every Borel subset A of T; deduce from b) the relations D(πn,μn)≤ε, D(π,μ)≤ε and show that limn→∞D(πn,π)=0.
e) The metric D on M+b is compatible with the tight topology (observe that M+b is metrizable for the tight topology).