Integration, V, p. 117
Bourbaki marks this one as harder than the rest.
Let Ti (1≤i≤n) be n locally compact spaces, μi a positive measure on Ti for 1≤i≤n. For each index i, denote by Ei the product ∏j=iTj; let fi be a function ≥0 on T=∏i=1nTi, measurable for μ=⨂i=1nμi and not dependent on ti; show that if, for 1≤k≤n, the function fkn−1 is integrable for the measure μ1⊗⋯⊗μk−1⊗μk+1⊗⋯⊗μn, then f1f2⋯fn is μ-integrable, and
∫f1f2⋯fndμ1dμ2⋯dμn≤(k=1∏nJk)1/(n−1)
where, for each index k, one sets Jk=∫fkn−1dμ1⋯dμk−1dμk+1⋯dμn (proceed by induction on n, applying the Lebesgue–Fubini theorem and Hölder’s inequality).
Deduce from this that if A is a μ-measurable subset of T, Ai its projection on Ei, and if Ai is integrable and of measure mi (for the measure ⨂j=iμj on Ei), then A is μ-integrable and
μ(A)≤(m1m2⋯mn)1/(n−1).
Examine the case of equality in these two inequalities.
Generalize to the case where, instead of considering the n products of n−1 of the Ti, one considers the (pn) products of p of the Ti, and where one integrates over T a product of (pn) functions ≥0 each of which depends on only p of the variables ti. For example, if Fij=Ti×Tj (i<j) and if fij depends only on the variables ti and tj, show that
∫(i<j∏fij)dμ1dμ2⋯dμn≤(i<j∏∫fijn−1dμidμj)1/(n−1).