Bourbaki

Exercise 13, § 8

Integration, V, p. 118

Bourbaki marks this one as harder than the rest.

Let (Tι)ι∈I(T_\iota)_{\iota \in I} be a family of compact spaces, and for each ι∈I\iota \in I, let μι\mu_\iota be a positive measure on TιT_\iota of total mass equal to 1. Let TT be the product space ∏ι∈ITι\prod_{\iota \in I} T_\iota, and μ\mu the product measure ⨂ι∈Iμι\bigotimes_{\iota \in I} \mu_\iota on TT (Ch. III, §4, No. 5).

a) For every ι∈I\iota \in I, let KιK_\iota be a compact subset of TιT_\iota; show that if K=∏ι∈IKιK = \prod_{\iota \in I} K_\iota then μ(K)=∏ι∈Iμι(Kι)\mu(K) = \prod_{\iota \in I} \mu_\iota(K_\iota).

b) Let MM be a compact subset of TT. Show that there exists a countable subset JJ of II such that, setting H=I−JH = I - J, TJ=∏ι∈JTιT_J = \prod_{\iota \in J} T_\iota, μJ=⨂ι∈Jμι\mu_J = \bigotimes_{\iota \in J} \mu_\iota, TH=∏ι∈HTιT_H = \prod_{\iota \in H} T_\iota, one has M⊂N×THM \subset N \times T_H, where NN is a μJ\mu_J-measurable subset of TJT_J such that μJ(N)=μ(M)\mu_J(N) = \mu(M). (Observe that for every n>0n > 0, there exists an open neighborhood of MM, the union of a finite number of elementary sets, whose measure differs from μ(M)\mu(M) by less than 1/n1/n.) From this, deduce that for almost every x∈Nx \in N, the section M(x)⊂THM(x) \subset T_H (when TT is identified with the product TJ×THT_J \times T_H) contains the product of the supports of the measures μι\mu_\iota for ι∈H\iota \in H (make use of the Lebesgue–Fubini theorem).

c) Show that if II is countable and if, for every ι∈I\iota \in I, AιA_\iota is a μι\mu_\iota-measurable subset of TιT_\iota, then the set A=∏ι∈IAιA = \prod_{\iota \in I} A_\iota is μ\mu-measurable and μ(A)=∏ι∈Iμι(Aι)\mu(A) = \prod_{\iota \in I} \mu_\iota(A_\iota).

d) Suppose that II is uncountable. For every ι∈I\iota \in I, let AιA_\iota be a μι\mu_\iota-measurable subset of TιT_\iota. For A=∏ι∈IAιA = \prod_{\iota \in I} A_\iota to be μ\mu-measurable, it is necessary and sufficient that one be in one of the following two cases: 1∘∏ι∈Iμι(Aι)=01^\circ \prod_{\iota \in I} \mu_\iota(A_\iota) = 0; 2∘2^\circ AιA_\iota contains the support of the measure μι\mu_\iota, except perhaps for the indices ι\iota of a countable subset of II. In each of these two cases, μ(A)=∏ι∈Iμι(Aι)\mu(A) = \prod_{\iota \in I} \mu_\iota(A_\iota). (Assuming that one is not in either of the two preceding cases, show that one can reduce to the case that μι(Aι)=1\mu_\iota(A_\iota) = 1 for all ι∈I\iota \in I. Using bb), show that neither AA nor T−AT - A can contain a compact set of nonzero measure.)

Solution

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Transcribed from the printed volume. Not translated.