Bourbaki

Exercise 16, § 8

Integration, V, p. 119

Bourbaki marks this one as harder than the rest.

Let (Tn)(T_n) be an infinite sequence of compact spaces, μn\mu_n a positive measure on TnT_n of total mass equal to 1, and μ\mu the product measure ⨂n=1∞μn\bigotimes_{n=1}^\infty \mu_n on T=∏n=1∞TnT = \prod_{n=1}^\infty T_n.

a) Let f be a function ⩾0\geqslant 0, μ\mu-integrable on T. Let (Ln)(L_n) be an increasing sequence of subsets of N\mathbf{N}, and, setting Mn=N−LnM_n = \mathbf{N} - L_n, let g=sup⁡nfLng = \sup_n f_{L_n}, h=sup⁡nfMnh = \sup_n f_{M_n} (the notations of Exer. 15). For every α>0\alpha > 0, let AαA_\alpha be the set of points t∈Tt \in T where g(t)>αg(t) > \alpha, and BαB_\alpha the set of points t∈Tt \in T where h(t)>αh(t) > \alpha. Show that α⋅μ(Aα)⩽∫fdμ\alpha \cdot \mu(A_\alpha) \leqslant \int f d\mu and α⋅μ(Bα)⩽∫fdμ\alpha \cdot \mu(B_\alpha) \leqslant \int f d\mu. (Observe that AαA_\alpha is the set of t∈Tt \in T where at least one of the fLn(t)f_{L_n}(t) is >α> \alpha, and express it as a countable union of sets GnG_n, pairwise disjoint and such that α⋅μ(Gn)⩽∫Gnfdμ\alpha \cdot \mu(G_n) \leqslant \int_{G_n} f d\mu.)

b) Suppose that (Ln)(L_n) is an increasing sequence of finite subsets of N\mathbf{N}, whose union is N\mathbf{N}. Show that fLnf_{L_n} tends almost everywhere to f, and that fMnf_{M_n} tends almost everywhere in T to the constant ∫fdμ\int f d\mu. (For every ε>0\varepsilon > 0, consider a continuous function g depending on only a finite number of variables and such that ∫∣f−g∣dμ⩽ε\int |f - g| d\mu \leqslant \varepsilon, and apply a) to the function ∣f−g∣|f - g|.)

Solution

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Transcribed from the printed volume. Not translated.