Bourbaki

Exercise 7, § 8

Integration, V, p. 115

Bourbaki marks this one as harder than the rest.

a) Let T, T' be two locally compact spaces; assume that T' admits a countable base. Let μ\mu be a positive measure on T, μ′\mu' a positive measure on T'. Let ff be a numerical function ≥0\geq 0 defined on T×T′T \times T', bounded on every compact subset of T×T′T \times T', and such that: 1∘1^\circ for almost every t∈Tt \in T, the function t′↦f(t,t′)t' \mapsto f(t, t') is μ′\mu'-measurable; 2∘2^\circ for every function h∈K(T′)h \in \mathscr{K}(T'), the function

t↦∫f(t,t′)h(t′)dμ′(t′), t \mapsto \int f(t, t') h(t') d\mu'(t'),
defined almost everywhere, is μ\mu-measurable. Show that, under these conditions, there exists a function gg, measurable for μ⊗μ′\mu \otimes \mu', such that for every t∈Tt \in T, one has f(t,t′)=g(t,t′)f(t, t') = g(t, t') except at the points of a μ′\mu'-negligible set AtA_t (depending on tt). (Show that for every function φ∈K(T×T′)\varphi \in \mathscr{K}(T \times T'), the function t′↦f(t,t′)φ(t,t′)t' \mapsto f(t, t') \varphi(t, t') is μ′\mu'-integrable for almost every t∈Tt \in T, and that the function t↦∫f(t,t′)φ(t,t′)dμ′(t′)t \mapsto \int f(t, t') \varphi(t, t') d\mu'(t'), defined almost everywhere, is μ\mu-integrable; one makes use of Lemma 1 of Ch. III, §4, No. 1. Observe next that φ↦∫dμ(t)∫f(t,t′)φ(t,t′)dμ′(t′)\varphi \mapsto \int d\mu(t) \int f(t, t') \varphi(t, t') d\mu'(t') is a positive measure on T×T′T \times T', with base μ⊗μ′\mu \otimes \mu', and apply the Lebesgue–Nikodym theorem; finally, use the fact that there exists a countable dense set in K(T′)\mathscr{K}(T').)

b) Suppose, moreover, that TT is metrizable. Show that the conditions of a) are satisfied if: 1∘1^\circ for almost every t′∈T′t' \in T', the function t↦f(t,t′)t \mapsto f(t, t') is μ\mu-measurable; 2∘2^\circ for almost every t∈Tt \in T, the function t′↦f(t,t′)t' \mapsto f(t, t') is continuous almost everywhere (for μ′\mu'). (Use Exer. 13 of Ch. IV, §5.)

c) Take T=T′=[0,1]T = T' = [0, 1]. Admitting the continuum hypothesis (S, Ch. III, §6, No. 4), let x≺yx \prec y be a well-ordering relation on TT for which there is no greatest element, and such that for every x∈Tx \in T, the set of z≺xz \prec x is countable. If one takes for μ=μ′\mu = \mu' Lebesgue measure, show that the characteristic function ff of the set of pairs (t,t′)(t, t') such that t≺t′t \prec t' satisfies the conditions of a), but that ∫f(t,t′)dμ(t)=0\int f(t, t') d\mu(t) = 0 for every t′∈T′t' \in T', and ∫f(t,t′)dμ′(t′)=1\int f(t, t') d\mu'(t') = 1 for every t∈Tt \in T.

Solution

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